C++ and C is still to seperate entities that can be merged together when needed. However, they are still seperate languages. They should still keep them seperated although they work simultaneously together.

Very useful links, thanks!

bro why we use %s in character's format specifier? %s is use for string na?

the questions asks us to read everything using a single cin statement and then print the output in different lines according the data types

sir the code doesn't work if i don't use space between %d and %ld in scanf function.why this is so?

can u tell me the use of 'fixed'??

it also works in this way...

cin >> a >> b>> c>> d>> e;
cout.precision(9);
cout <<fixed<<a<<endl<<b<<endl<<c<<endl<<d<<endl<<e<<endl;

can u please elaborate the use of fixed and precision. and what is the use of function using?

why "%i" and "%li" shouldn't it be "%d" and "%ld"

cout.precision(3); cout<

bro why we use this code instead of this code
 cout<<d<<endl;
cout<<e<<endl;

what is the difference ??

what is difference between %.3 and %.03 ?

thanks the first code solution worked for me. they caught iostream as an error. so I never used it. but I used all the other code statements

Will we have to cout multiple times or is there any other way?

What is Fixed used for ?

To set Float and Double Precision:

Add a Header: include

1. syntax: To set FLoat to Precision 3 cout<

2. syntax: To set Double to precision 9 cout<

what is meant by precision

what about zeroes at the end of double value how to print them

Hey,

Anyone know why this is not accepted? It seems to produce the desired output but is marked as incorrect...

int main() { int i; long l; char c; float f; double d;

scanf("%d %ld %c %f %lf", &i, &l, &c, &f, &d);

printf("%d", i);
printf("\r");
printf("%ld", l);
printf("\r");
printf("%c", c);
printf("\r");
printf("%.3f", f);
printf("\r");
printf("%.9lf", d);

return 0;

}

I had to change the precision numbers according to the sample input given in the question.

why in statement "cout<

bro why .03. why not .3??? what difference it brings??

For me the above solution is showing wrong answer.

I tried it this without fix but then it does not pass some of the test cases..Why so??

i had same problem to print last two. please help me to solve this.

for C++:

use cout.precision(n);

Same here. An update in the problem displayed would be helpful.

It works! thank you

YOU are missing the point: scanf and printf DON'T use the data type !!!

This is the anti-example for data types

but what is iomanip and setprecision?why it is used?

I am doing the same as above and getting same result .So someone can explain why i'm getting 3 test case fail..?

Problem description also says, use printf and scanf, try to submit using printf and scanf and let me know what is the result

For your reference, this is how problem statement teaches you to use scanf and printf:

#include <iostream>
#include <cstdio>

using namespace std;

int main() {
    int i;
    long l;
    long long ll;
    char c;
    float f;
    double d;

    scanf("%d %ld %lld %c %f %lf", &i, &l, &ll, &c, &f, &d);
    printf("%d\n%ld\n%lld\n%c\n%f\n%lf", i, l, ll, c, f, d);

    return 0;
}

See the number of decimals in the output. you will know what to use instead of "cout" ;)

The issue is that the double input is not printed with full precision using cout. You have to set the precision you want before you print it.

For example, with your code above, on an input of 111134.22344, it will print just 111134.2

Hint: Read about setprecision()

iam also doing the same thing only 1 test passed

http://stackoverflow.com/questions/554063/how-do-i-print-a-double-value-with-full-precision-using-cout

same here the output of double 'd' is coming wrong

setprecision should be used for rounding off last two inputs as they are floating point numbers and are needed to be rounded off to 2 and 5 decimal points.

first i tried my program same as you but failed 3 testcases ,then i tried like this,,,,,,,,,, int main() { int a; long int b; long long int c; char d; float e; double f; scanf("%d %ld %lld %c %f %lf",&a,&b,&c,&d,&e,&f); printf("%d\n%ld\n%lld\n%c\n%f\n%lf",a,b,c,d,e,f); return 0; }it passed all testcases successfully ,

cin each variable separately, that should work. eg. cin>>n; cin>>l; and so on...

int main() { int a; cin >> a; long b; cin >> b; long long c; cin >>c; char d; cin >> d; float e; cin >> e; double f; cin >> f; cout << a << endl << b << endl << c << endl << d << endl;
cout.precision(10); cout << f << endl; return 0; }

this will let you pass testcase 2

as that ..why failed in last 3 test ??

int main() {

int i;
long int l;
long long int ll;
char c;
float f;
double d;
cin>>i>>l>>ll>>c>>f>>d;
cout<<i<<"\n"<<l<<"\n"<<ll<<"\n"<<c<<"\n"<<f<<"\n"<<d;
return 0;

}

also with my code, I'm confused why only pass testcase0

me too

same here !!!!!!!!!!!!

You have to use setprecision() for the float number ! it will now pass the second test lol ..

I also faced the same problem, use and set precision by setprecision(n); and then fixed

include

include

include

using namespace std;

int main() {

int a;
long b;
long long c;
char d;
float e;
double f;
int n;
cin>>a>>b>>c>>d>>e>>f;
cout<<a<<endl<<b<<endl<<c<<endl<<d<<endl;

cout << setprecision(15)<<e<<endl<<f;
return 0;

}

You haven't set the precision for float and double values. Read above given threads also. For f and d you should write as: cout<

Also use #include

yess .. its true what happens to rest tastcases..

put %d,%ld,%lld,%c,%f,%lf in scanfand printf

me too bro

cin >> a >> b>> c>> d>> e;
cout.precision(9);
cout <<fixed<<a<<endl<<b<<endl<<c<<endl<<d<<endl<<e<<endl;

try this.

http://www.cplusplus.com/reference/iomanip/setprecision/

Take another variable 'temp' and then type : temp=scanf(...); it is need not to printf temp;

can someone tell me if i made a mistake. i also apologise for it being a bit messy, but i couldn't put this into a table. to try make things easier to read, i bolded each colmn.

Type Size (bytes) Range-Minimum Range- Maximum

Character 1 -128 127 Unsigned Char 1 0 255 Signed Char 1 -128 127 Integer 4 -2,147,483,648 2,147,483,647 Signed Int 4 0 4,294,967,295 Unsigned Int 4 -2,147,483,648 2,147,483,647 Short Int 2 -32,768 32,767 Signed short Int 2 0 65,535 Unsigned Short Int 2 -32,768 32,767 Long Int 4 -2,147,483,648 2,147,483,647 Signed Long Int 8 0 4,294,967,295 Unsigned Long Int 8 -2,147,483,648 2,147,483,647 Float 4 1.8E-38 3.4E+38 Double 8 2.2E-308 1.8E+308 Long Double 8 2.2E-308 1.8E+308 Bool 1 True/False True/False Wchar_t 2 or 4 0 65,535 http://www.besanttechnologies.com/training-courses/php-training/php-training-institute-in-chennai | http://www.trainingintambaram.in/php-training-in-chennai.html