Oceloctopus int main() { int in; string num[10] = {"Greater than 9", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"}; cin >> in; if(in > 9){ cout << num[0]; } else{ cout << num[in]; } return 0; }I really don't like large if/switch chunks.
backwater [deleted]angel1a It's helpful. My switch chunks are really complicated.
Rayhan_Mahmud This is really cool !
apasa003 Awesome one.
emirhanptk ty for helping
omike1900 awesome!
alrafikp Wow!Great!
essamgouda97 i knew the solution but came here because I knew someone would have a far more creative one
iam_nevets Me too, haha...I didn't wanna write a long code.
knorful I chuckled from this. This is awesome!
aweshashmi786 Thanks Oceloctopus .
PavithraMurthy really a good example and great
rajatchauhan it's good...You thought in a different way
dixondavid1380 Very helpful! Thank you!
surajsrikanth509 cool buddy
kjdpogo No need for any if statements:
int n; const char *words[] = {"one","two","three","four","five","six","seven","eight","nine"}; cin >> n; cout << ((n<= 9) ? words[n-1] : "Greater than 9") << endl;
Mohit_Yadav_389 why you made a '*' sign in words?
kjdpogo Because it's an array of "const char *"
eyeslife isn't the "*" indicating that the array is fixed in the memory location? I mean astrics are used for referencing a memory address and so on so ultimately the "char" part doesn't necessarily make the use of astrics a must.
richard12 No - not in that sense, really. The *words is part of the definition of the variable words, indicating that it's a pointer. That's part of its type.
When you use a * in a dereferencing expression, then it's referring to the location of the pointer variable.
(A * can also mean an arithmetic multiplication. It's context dependant.)
Mohit_Yadav_389 BTW this is manipulation of if else statement!
kjdpogo Technically it's the ternary operator, which is not an if-else statement.
alaniane Technically, the ternary operator is an if-else statement. Look at what is generated in assembly and you will see that an if-else and a ternary operator generate the same instructions. The ternary operator is just a shorthand form of the if-else and many cases it is better to use the if-else clause. If you use the ternary operator for anything more than a simple test condition, you will not be able to take advantage of the compiler's optimizations.
diddly_chops technically, no it is not an if-else statement. a ternary expression is an expression, an if-else statement is a statement. This distinction matters sometimes, even if the assembly generated is the same in this case.
kumarpalnahar Its really a gud 1....short n best
p_rzetelski_note @kjdpogo beautiful
ratner2 The question mark operator is an if/else statement which makes reading your code more difficult. IMHO.
geraldfeu This clearly means you know your C++. And technically you are using an if statement in your cout statement.
khan207 thsi is on another level
suhasdotcom @Oceloctopus: A really creative solution.
wheresbicki This is a great approach. I've always hated writing down large switch statements. I'm gonna use this for implementing error code messages.
b6032682 very nice.
ankeshk690 [deleted]w_ingham Apparently you don't like unneccessary preprocessor directives taking up space in your IDE either, lol.
raviyadav13652 include
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using namespace std;
int main(){ int n; cin >> n; if(n==1) { cout<<"one";
} else { if(n==2) {cout<<"two"; } else { if(n==3) { cout<<"three";} else{ if(n==4) {cout<<"four";} else{ if(n==5) {cout<<"five";} else{ if(n==6) { cout<<"six"; } else{ if(n==7) {cout<<"seven"; } else{ if(n==8) { cout<<"eight"; } else{ if(n==9) {cout<<"nine"; } else{ cout<<"Greater than 9"; } } } } } } } } } return 0;}
yashdeep141999 int main(){ int n; cin >> n; if(n>9) cout<<"Greater than 9"; else { switch(n) { case 1: cout<<"one"; break; case 2: cout<<"two"; break; case 3: cout<<"three"; break; case 4: cout<<"four"; break; case 5: cout<<"five"; break; case 6: cout<<"six"; break; case 7: cout<<"seven"; break; case 8: cout<<"eight"; break; case 9: cout<<"nine"; } } return 0; }
this one is better
Kwydin You could omit the if/else since switch has a default option if it doesn't fit the other cases :)
switch(n){ case 1: cout<<"one"; break; case 2: cout<<"two"; break; case 3: cout<<"three"; break; case 4: cout<<"four"; break; case 5: cout<<"five"; break; case 6: cout<<"six"; break; case 7: cout<<"seven"; break; case 8: cout<<"eight"; break; case 9: cout<<"nine"; break; default: cout<<"Greater than 9"; }
sancz I think the code will fail if input is 0. But it is not in constraints condition though. I think you are good to go.....
urav06 [deleted]sriramya_ec_vcet condtion itself wrong n is between 0 and 10 so only 9 char only possible
elassaad_y Pass this condition: if(n >=1 && n <= 9)
sagarakbari17 WRITE THIS
int n; string a[]= {"Greater than 9", "one", "two", "three", "four", "five", "six", "seven", "eight", " nine"}; cin >> n; if(n<=9){ cout<
satyakibose98 But how are you printing the whole sentence?
divyanshhardia10 you rule
jitucoder thnx man for the different perspective. It's really cool.
pratyakshdua1997 superb man.
m13733125839 So creative!
nguyenminhquan21 cool
aditya141199 gud one
gauravkhatri2698 I also like short and efficient programs
DenavoAyush very good short method
phanhoang_le Bezt algorithm <3
diablo_ayman good and simple i start to learn c++ so i search hashmap in it and use it but this is simpler than my solution
arizsiddiqui That's neat.
waasepur really shortcut and tricky solution
Aminson_Jets You forgett to add string num[11] and " ten" on the endline.
like this: string num[11] = {"Greater than 9", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten"};
Aminson
russellkemmitde1 This is awesome! I wrote a switch statement and was thinking there had to be a better way to do this! Great job bud!
singhsachin78789 please explain it
grinning_moon_c1 Neat!
longhuang Awesome!
zuhaibkhan629 i appreciate your source code.. but what will be your desired output?? if we input negative number..
kuwarsarthaksin1 output for else is num[in],testcase is not running... what is the problem??
khan207 helpful!
chinthahareeshk1 [deleted]
Mhd_Tahawi isn't "switch" statement a better fit for this case ?
corredorcatino Yes, it is. But I think that the purpouse of the problem is to test your knowledge of if/else;
balakram in case of switch is what is wrong
Azi91 I used a switch statement and it worked.
ujjawal18singh [deleted]
RA1511008010465 yaa i do think so
meaux an array less typing. less typing is less work.
yeah, it's lazy.
metahost Just 'cause no one likes chunky if-else blocks.
#include <string> #include <iostream> using namespace std; int main(){ int n; cin >> n; string int_map[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"}; if (n > 9) { cout << "Greater than 9" << endl; } else { cout << int_map[n-1] << endl; } return 0; }
elassaad_y Here is a version of your code that accepts all possible answers, like negative integers or 0:
int main(){ int n; cin >> n;
string x[] = {"Greater than 9", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"}; if (n < 0 || n > 9) { cout << x[0] ; } else { cout << x[n] ; } return 0;}
alaniane Except that would introduce a logical bug since -1 is not greater than 9.
kentcrobbins394 -1 is not one of the values that is tested in the problem. In other scenarios though, you would be correct.
alaniane Since -1 is not a valid being tested then why even include the statement: n < 0. Instead just use:
if(n > 9){ ... }else{ ... }
The problem above also has a logic error if n = 0 since it will print "Greater than 9" because x[n]= "Greater than 9"
I know it will pass the test cases; however, since "everyone" seems to be using this site to hire programmers then the code presented should be written for professional quality and not just to pass an inadequate test case set.
abdulmutaalazhar What is the purpose of the following line:
cin.ignore(numeric_limits::max(), '\n');
Can someone please explain
Mohammed_Abdelh1 int main(){ string arr[]={"Greater than 9","one","two","three","four","five","six","seven","eight","nine"};
int n; cin>>n; if(n>0&&n<=9) cout<<arr[n]; else cout<<arr[0]; return 0;}
yoyis540 ofcourse there are better sophisticated ways of making the code shorter and more flexiable but here is nothing that works too but fails lol int main() { int n; cout << "Enter your digit:"; cin >>n; if (n == 1) { cout << "one" << endl; } if (n == 2 ) { cout << "two" << endl; } if (n == 3) { cout << "three" << endl; } if (n == 4) { cout << "four" << endl; } if (n == 5) { cout << "five" << endl; } if (n == 6) { cout << "six" << endl; } if (n == 7) { cout << "seven" << endl; } if (n == 8) { cout << "eight" << endl; } else if ( n > 9) { cout << "n=" << n << " " << "is greater than 9" << endl; } return 0; }
vinu007 int in; string num[10] = {"Greater than 9", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
cin >> in;
if(in > 9){ cout << num[0]; } else{ cout << num[in]; }
demure #include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; cin.ignore(numeric_limits<streamsize>::max(), '\n'); string s[10]={"one","two","three","four","five","six","seven","eight","nine","Greater than 9"}; cout<<(n>9?s[9]:s[n-1]); return 0; }
amitkathait20 this is a good example , its use if, else ,switch case very easy.
include
include
using namespace std;
int main() { int n; cin >> n;
if (n==1){ cout<<"one"; } else if (n==2){ cout<<"two"; } else if (n==3){ cout<<"three"; } else if (n==4){ cout<<"four"; } else if (n==5){ cout<<"five"; } else if (n==6){ cout<<"six"; } else if (n==7){ cout<<"seven"; } else if (n==8){ cout<<"eight"; } else if (n==9){ cout<<"nine"; }
else if (n>=9){ cout<<"Greater than 9"; } else{ cout<<"........"; } // Write Your Code Here
return 0;}
deepakkryad std::unordered_map m1{{1, "one"},{2, "two"}, {3, "three"}, {4, "four"}, {5, "five"}, {6, "six"}, {7, "seven"}, {8, "eight"}, {9,"nine"} };
//,"two","three", "four","five","six","seven","eight","nine"}; if (n >= 1 && n <= 9) { auto data = m1.find(n); cout<<data->second<<endl; } else { cout << "Greater than 9"; }
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