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  1. Prepare
  2. C++
  3. Introduction
  4. For Loop
  5. Discussions

For Loop

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  • Raja_516
     + 0 comments

    Now we encounter the problem based on the basics of c++ ; "we can't use datastructures or any arrays".

    so I get the code

    CODE :

    include

    include

    using namespace std;

    int main() { // Complete the code. int n,m;

    cin>>n>>m;
// cout<<n<<m;
for(int i=n;i<=m;i++){
    if(i==1){
        cout<<"one"<<"\n";
    }
    else if(i==2){
        cout<<"two"<<"\n";
    }
    else if(i==3){
        cout<<"three"<<"\n";
    }
    else if(i==4){
        cout<<"four"<<"\n";
    }
    else if(i==5){
        cout<<"five"<<"\n";
    }
    else if(i==6){
        cout<<"six"<<"\n";
    }
    else if(i==7){
        cout<<"seven"<<"\n";
    }
    else if(i==8){
        cout<<"eight"<<"\n";
    }
    else if(i==9){
        cout<<"nine"<<"\n";
    }
    else if(i>9){
        if(i%2 ==0){
            cout<<"even"<<"\n";
        }
        else{
            cout<<"odd"<<"\n";
        }
    }
}
return 0;

    }

    }

  • ali_dev423
     + 0 comments
    int main() {
    string words[] = {
        "one", "two", "three", "four", 
        "five", "six", "seven", "eight", 
        "nine"
    }; 
    
    int a, b; 
    cin >> a;
    cin >> b; 
    
    for (int i = a; i <= b; i++) {
        if(i >= 1 && i <= 9) {
           cout << words[i - 1] << "\n"; 
        }
        else if (i > 9) {
            if( i % 2 == 0) {
                cout << "even \n"; 
            }
            else {
                cout << "odd \n"; 
            }
        }
    }
    
    return 0;
}

  • afuzzyduck
     + 0 comments
    int main() {
    // Complete the code.
    string number_str[11]= { 
    "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "even", "odd"
};
    
    int a = 0, b = 0, idx = 0;
            
    scanf("%d\n%d", &a, &b);
    
    for (int i=a; i <=b; i++) {
      idx = (i>0 && i<10) ? i-1 : i%2+9;
      printf("%s\n", number_str[idx].data());
    }

    return 0;
}

  • saikakumanu2003
     + 0 comments

    int main() { int a,b ; cin>>a>>b; string x[]={"one","two","three","four","five","six","seven","eight","nine"}; for(int i=a ;i<=b;i++){ if(i<=9){ cout<9 && i%2==0){ cout<<"even"< 

    return 0;

    }

  • yashdeora98294
     + 0 comments

    Here is For loop in c++ solution - https://programmingoneonone.com/hackerrank-for-loop-solution-in-cpp.html