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  1. Prepare
  2. C++
  3. Introduction
  4. For Loop
  5. Discussions

For Loop

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  • Chelseamensah2
     + 0 comments

    test case 0 is very misleading. Did not give clear directions

  • KinetKinet
     + 0 comments

    I looked for solutions in here but I want to do it with only what informations they provided, so I did this.

    #include <iostream>
#include <cstdio>
using namespace std;


int main() {
  
 int a, b;
 cin >> a >> b;
  for ( int i = a; i <= b; i++) {
    
    if (i == 1) {
      cout << "one" << endl;
    }
    else if (i == 2) {
      cout << "two" << endl;
    }
    else if (i == 3) {
      cout << "three" << endl;
    }
    else if (i == 4) { 
      cout << "four" << endl;
    }
    else if (i == 5) {
      cout << "five" << endl;
    }
    else if (i == 6) {
      cout << "six" << endl;
    }
    else if (i == 7) {
      cout << "seven" << endl;
    }
    else if (i == 8) {
      cout << "eight" << endl;
    }
    else if (i == 9) {
      cout << "nine" << endl;
    }
    else if ( i > 9 && i % 2 == 0 ) {
      cout << "even" << endl;
    }
    else {
      cout << "odd" << endl;
    }
    
  }
  return 0;
}

  • Nicker_X
     + 0 comments

    Testcases don't correspond to the description. Only the first (basic) testcase does. The description demands to supply integers "separated by a newline." whereas most testcases supply integers separated by a whitespace, so the first submission is likely doomed to fail if you try to carefully follow the description...

  • indrarajdangi822
     + 0 comments

    why this code is unable to pass test case ??

    include

    include

    using namespace std;

    int main() {

    string s[10]={"one","two","three", "four","five","six","seven","eigth","nine"}; int x,y ; cin>>x>>y; for(int i=x; i<=y;i++) { if(i>=1 && i<=9) { cout<9 && i%2==0) { cout<<"even"<

  • LyonLad
     + 0 comments

    What I wrote...

    #include <iostream>
#include <cstdio>
#include <string>
using namespace std;

int main() {
    
    string s[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"}; 
    int a, b;
    cin >> a >> b;
    
    for(int i = a; i<=b; i++) {
        if (i<=9) {
        cout << s[i-1] << endl;
        } else if (i>9 && i%2==0) {
            cout << "even" << endl;
        } else {
            cout << "odd" << endl;
        }
    }              
    return 0;
}
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