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2 days ago+ 0 comments

import calendar

# collect information about mm, dd, and yy while converting into integers
mm, dd, yy = (int(i) for i in input().split())


# Returns the day of the week. Monday is zero.
weekday = calendar.weekday(yy,mm,dd)

# day_name takes an array and returns the name of the weekday associated with the value inside of our array.
# It can not return multiple weekdays. 
# I.E our array cannot have multiple values inside of it

print(calendar.day_name[weekday].upper())

2 weeks ago+ 1 comment

Another oneliner, (year > 2000)

print( (lambda m, d, y: ['SATURDAY', 'SUNDAY', 'MONDAY', 'TUESDAY', 'WEDNESDAY', 'THURSDAY', 'FRIDAY'][int((int(d)+[0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365][int(m) - 1]-(not int(y)%4 and int(m)<3)+(int(y)-2000)*365.25)%7)])(*input().split()) )

3 weeks ago+ 0 comments

Enter your code here. Read input from STDIN. Print output to STDOUT

import calendar import datetime date_time = input().split() month = date_time[0] day = date_time[1] year = date_time[2]

day_number = calendar.weekday(int(year), int(month), int(day)) day_name = calendar.day_name[day_number] print(day_name.upper())

4 weeks ago+ 0 comments

import calendar
mm, dd, yy = map(int, input().split())
print(calendar.day_name[calendar.weekday(yy,mm,dd)].upper())

4 weeks ago+ 0 comments

---------------------------------------MY SOLUTION--------------------------------------

Assign values to three vars (day, month, year) using string index.
Store the calendar in a variable. cal = calendar.weekday(year, month, day)
Create a list to hold days of the week starting from monday. (0th element is monday).
Iterate over the list elements and print out the respective list element which is equal to the value in cal variable https://colab.research.google.com/drive/12QEMyeN8SyuFAxjwgKdLcqMm__0gV5rT?usp=sharing

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