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  1. Prepare
  2. Algorithms
  3. Strings
  4. CamelCase
  5. Discussions

CamelCase

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1910 Discussions

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  • jonathan_aceves1
     + 0 comments
    def minimumNumber(n, password):
    # Return the minimum number of characters to make the password strong
    minLength = 6
    patterns = [r'[0-9]', r'[a-z]', r'[A-Z]', r'[!@#$%^&\*\(\)\-\+]']
    total_chars = sum([1 for pattern in patterns if not re.search(pattern, password)])
    total_chars += (0 if minLength <= n + total_chars else minLength - n - total_chars)
    return total_chars

  • gopikan299
     + 0 comments

    my python solution

    def camelcase(s):

    tot = 1
for char in s:
    if char.isupper():
        tot += 1
return tot

  • mdsanz
     + 0 comments

    My Java 8 Solution

    public static int camelcase(String s) {
        int count = 1;
        
        for (char c : s.toCharArray()) {
            if (Character.isUpperCase(c)) {
                count++;
            }
        }
        
        return count;
    }

  • yashdeliwala10
     + 0 comments

    my cpp solution for this programme

    int camelcase(string s) {

    int count=1;  //  count=1 for min 1 word
for(int i = 0;i <s.size();i++){ // loop lessthan size
    if(s[i] < 'a')   //if less than lowescase than count++
    count++;
}

return count;

    }

  • afzal_saiyed931
     + 0 comments

    def camelcase(s): # Write your code here wordCount = 1 for i in s: if "A" <= i <= "Z": wordCount += 1

    return wordCount