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  1. Practice
  2. Algorithms
  3. Greedy
  4. Candies
  5. Discussions

Candies

  • mansi1795 + 3 comments

    i did exactly the same,however it failed two test cases :(

    • kwiatek999 + 3 comments

      I had the same - I think you accumulate the result on an int that is overflowing, try long long

      • vvvincentvan + 0 comments

        I think the problem might be that it's not exactly up or down trends, when you go throuth the sequence from both side, and meet in the middle, you don't have to raise all the value in the left part or the right part. I think the best way is divide and conquer algorithm.

      • enricogiurin + 0 comments

        I had the same 2 tests failing. It was enough to save the sum in a long, rather than in a int.

      • animeshy2jj + 0 comments

        Using long worked for me.

    • nikunj_gupta447 + 4 comments

      try this test case:-

      10
      9 2 3 6 5 4 3 2 2 2

      • vicky2922 + 3 comments
        [deleted]
        • gauravagarwal271 + 0 comments

          how answer will be 20?

        • ranchoparikh + 0 comments
          [deleted]
        • rav_gupta11 + 3 comments

          how it is 20?

          • rav_gupta11 + 2 comments

            In your solution '<' should be there instead of '<=', read first solved example.

            • vicky2922 + 0 comments
              [deleted]
            • vicky2922 + 4 comments
                  for(int i = 1 ; i < n  ;i++){ //forward track
        if(arr[i] > arr[i-1]){
            dp[i] = dp[i] + dp[i-1]; 
        }
    }

    for(int i = n-2 ; i >= 0 ; i--){ // back track
        if(arr[i] > arr[i+1] && dp[i] <= dp[i+1]){
            dp[i] = dp[i+1] + 1;
        }
    }

    its 22 ..
              • paul_dirac + 0 comments
                [deleted]
              • khushlanipiyush + 1 comment

                I don't think it's a true dp as we are doing reinforcement in the dp array which is not done generally. I also had somewhat same solution but my array name was not dp as mentioned earlier.

                • ariellyrycs + 2 comments

                  9 2 3 6 5 4 3 2 2 2

                  1,1,2,3,1,1,1,1,1,1 right

                  2,1,1,5,4,3,2,1,1,1 left

                  find out the max for each reasult

                  2,1,2,5,4,3,2,1,1,1

                  2+1+2+5+4+3+2+1+1= 20

                  • paullb + 0 comments
                    [deleted]
                  • anmolmittal53 + 0 comments

                    brother your maths need to be brushed up first off all you havn't included the last (1) in your result and even if you have not included, you haven't sum up all the values right 2+1+2+5+4+3+2+1+1 = 21

              • yashiagarwal1812 + 0 comments

                how is this working i am unable to get it . could you please explain

              • yashiagarwal1812 + 0 comments
                [deleted]
          • CRAZYGUY2704 + 0 comments
            [deleted]
          • CRAZYGUY2704 + 0 comments
            [deleted]
      • thakkarjinal99 + 0 comments
        [deleted]
      • smritirastogi33 + 0 comments

        22?

      • rutulpatel2000 + 0 comments
        [deleted]
    • nikitac + 0 comments

      take the data type of result as long long int instead of int