Discussion on Cats and a Mouse Challenge

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15 hours ago+ 0 comments

int[] dist = {0,0}; dist[0] = Math.Abs(z-x); dist[1] = Math.Abs(z-y); return (dist[0] == dist[1]) ? "Mouse C" : (dist[0] < dist[1]) ? "Cat A" : "Cat B";

1 day ago+ 0 comments

if(abs(x-z)< abs(y-z))
        return "Cat A";
    else if(abs(x-z)> abs(y-z))
        return "Cat B";
    else
        return "Mouse C";

4 days ago+ 0 comments

JavaScript

    let a = Math.abs(x-z);

    let b = Math.abs(y-z);
if (a == b){
    return "Mouse C"
}
else if (a<=b){
    return "Cat A"
}
 else if (a>=b){
    return "Cat B"
}

1 week ago+ 0 comments

My Java 8 solution, feel free to ask me any questions.

static String catAndMouse(int x, int y, int z) {
    int catADistance = Math.abs(x - z);
    int catBDistance = Math.abs(y - z);
    
    if(catADistance == catBDistance) {
        return "Mouse C";
    }
    
    if(catADistance > catBDistance) {
        return "Cat B";
    }
    
    return "Cat A";
}

2 weeks ago+ 0 comments

Python3:

def catAndMouse(x, y, z):
    catADistance = abs(x - z)
    catBDistance = abs(y - z)
    if catADistance == catBDistance: return "Mouse C"
    return "Cat A" if catADistance < catBDistance else "Cat B"

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