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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Cats and a Mouse
  5. Discussions

Cats and a Mouse

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  • amiya13
     + 11 comments

    this problem should be of 10 points, not 15

  • Soumyadeep_B
     + 5 comments

    Python 3:

    def catAndMouse(x, y, z):
    a = abs(x-z)
    b = abs(y-z)
    
    return "Cat A" if a<b else "Cat B" if b<a else "Mouse C"

  • epiccaterpi11er
     + 1 comment

    one line c++:

    string catAndMouse(int x, int y, int z) 
{
    return (abs(x - z) < abs(y - z)) ? "Cat A" : (abs(x - z) > abs(y - z)) ? "Cat B" : "Mouse C";
}

    how is this worth 15 points lol

  • francois_bracha1
     + 4 comments

    The default C++ code is nonsense. 

    for(int a0 = 0; a0 < q; a0++){
    int x;
    int y;
    int z;
    cin >> x >> y >> z;
    vector <string> result = catAndMouse(x, y, z);
    for (ssize_t i = 0; i < result.size(); i++) {
        cout << result[i] << (i != result.size() - 1 ? " " : "");
    }
    cout << endl;
}

    There's no point in expecting the user to return a sentence by filling a vector with single words in order to print them separated with spaces. I think it is counter-intuitive and needlessly confusing, and it should be refactored like so:

    for (int a0 = 0; a0 < q; a0++)
{
	int x, y, z;
	cin >> x >> y >> z;
	string result = catAndMouse(x, y, z);
	cout << result << endl;
}

    with the return type of catAndMouse changed to string.

  • danielbiocchi
     + 5 comments

    java 8:

        static String catAndMouse(int x, int y, int z) {
            
        if(Math.abs(x - z) < Math.abs(y-z)){
            return "Cat A";
        }
        else if (Math.abs(x - z) > Math.abs(y-z)){
            return "Cat B";
        }
        else{
            return "Mouse C";
        }

    }
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