We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Algorithms
  3. Implementation
  4. Chocolate Feast
  5. Discussions

Chocolate Feast

  • beckwithdylan
     + 1 comment

    Here's your one-liner

    print(*(n//c+(n//c-1)//(m-1) for n,c,m in [map(int,input().split()) for _ in range(int(input()))]),sep='\n')