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  1. Prepare
  2. Algorithms
  3. Dynamic Programming
  4. Choosing White Balls
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Choosing White Balls

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  • wendllandmkl
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    This problem really tests your understanding of probability — great challenge! By the way, for anyone planning to work or travel abroad, you might find this helpful: online nbi clearance application.

  • wendllandmkl
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    Really interesting discussion here — probability problems like this always make you think differently! On a side note, if you're curious How common is your name, I found a cool tool that shows it.

  • zoyashah41306
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  • yashparihar729
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    Here is my soltuion in java, javascript, python, C, C++, Csharp HackerRank Choosing White Balls Solution

  • sunaluak
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    What am I missing here?

    Test case: 4 2 WWBW has expected answer of 1.8333333333. The only way to get that answer based on the very limited instruction case logic is as follows: Level 1: WWBW = 1 - you can get a white ball every time. Level 2: WBW and WWB. WBW = 2/3 WWB = 1

    Final answer: (2/3 + 1) / 2 (for the two row possibilities in level 2) + 1 for the original = 1.833333 Ok, cool, so far so good.

    Following that logic, Test case: 5 3 WWWBW Level 1: WWWBW = 1, you can get a white ball every time.

    Level 2 has two unique row possibilities: WWBW and WWWB. WWBW = 1

    Level 3 for WWBW has two unique rows: WBW and WWB: WBW = 2/3 and WWB = 1 and add (2/3 + 1) / 2 to WWBW's 1 for a total of 1.91666666 for the WWBW possibility.

    WWWB = 1

    Level 3 for WWWB has only one unique row possibility, WWB, which is also 1.

    so, WWWB has a total white ball probability of 1 + (1/1) = 2.

    Then, going back up to level 1, divide both the WWBW and WWWB row totals by 2 and add to the original 1 for WWWBW for a total of 2.9166666.

    But, the expected test case answer is 2.9000000000. Can anyone explain please?