We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
Loading...
  1. Practice
  2. Algorithms
  3. Implementation
  4. Circular Array Rotation
  5. Discussions

Circular Array Rotation

  • murnun + 1 comment

    Nice one liner using the built in functions! Unfortunately, this still fails when k is higher than n (test case #4). You seem to be getting around it by overwriting k with: 

    var k = details[1]%details[0];

    I'm curious to see if there are other, more algorithmic solutions to this in Javascript.

    • matt_heisig + 1 comment

      This works in Javascript for all test cases:

      function main() {
    var n_temp = readLine().split(' ');
    var n = parseInt(n_temp[0]);
    var k = parseInt(n_temp[1]);
    var q = parseInt(n_temp[2]);
  
    a = readLine().split(' ');
    a = a.map(Number);
  
    for (var i=0; i<q; i++) {
      var m = readLine();
      console.log(a.slice(m-k%n)[0]);
    }
}
      • mehul_sachdeva7 + 1 comment

        when i ran my code only sample test cleared and rest failed

        function circularArrayRotation(a, k, queries) { 

    var res = [];
    var resind = 0;

    while (k > 0) {
        rotateArr();
        k--;
    }

    function rotateArr() {
        var i = 0;
        var lastel = a[a.length - 1];
        var temp1 = a[0];
        var temp2;

        while (i < a.length-1) {
            temp2 = a[i + 1];
            a[i + 1] = temp1;
            temp1 = temp2;
            i++;
        }

        a[0] = lastel;
    }

    for(var j in queries) {
        res[resind] = a[j];
        resind++;
    }

    return res;
		}

            I think some issue is in how i am returning the values, please help identify the error
        • mehul_sachdeva7 + 1 comment

          found out what the problem was, new JS code:

          function circularArrayRotation(a, k, queries) {

    var rarr = [];
    var aind = [];
    var res = [];

    for (var i = 0; i < a.length; i++){
        if ((i + k) < a.length) {
            aind[i] = i + k;
        } else {
            aind[i] = (i + k) % a.length;
        }
    }

    for (var j = 0; j < a.length; j++) {
        rarr[aind[j]] = a[j];
    }


    for (var k = 0; k < queries.length; k++){
        res[k] = rarr[queries[k]];
    }

    return (res);
}
          • tashk85 + 0 comments

            Hi, could you please explain what is happening here? Thanks