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collections.Counter()
collections.Counter()
+ 0 comments from collections import Counter X = int(input()) shoes = Counter(map(int,input().split())) # "4 5 6 7 7" # ["4","5","6","7","7"] # [4,5,6,7,7] # {4:1,5:1,6:1,7:2} N = int(input()) earned = 0 for i in range(N): size,price= map(int,input().split()) if shoes[size] > 0: shoes[size]-=1 earned += price print(earned)
+ 0 comments from collections import Counter shoe_total = int(input().strip()) shoe_list = list(map(int, input().split())) customers = int(input()) count_shoes = Counter(shoe_list) total = 0 for _ in range(customers): shoe_size, price = list(map(int, input().split())) if count_shoes[shoe_size] > 0: count_shoes[shoe_size] -=1 total += price print(total)
+ 0 comments from collections import Counter x = int(input().strip()) shoes = list(map(int, input().split())) shoe_counter = Counter(shoes) N = int(input().strip()) revenue = 0 for i in range(N): size, price = map(int, input().split()) if shoe_counter[size] > 0: revenue+=price shoe_counter[size] -= 1 elif shoe_counter[size] == 0: del shoe_counter[size] revenue +=0 print(revenue)
+ 0 comments I could have done this in a really short stint of code but wanted to build it more like an actual program so I broke it down into its basics and structured it more like a real world program would be.
# Enter your code here. Read input from STDIN. Print output to STDOUT def calculate_total_revenu(shoes_available=None, customers=None): ''' input's shoes_available - A dictionary item where key=shoe_size value=number_pairs_available customers - A list of customers and their desired shoe size and sale price. returns total_revenue as an integer value. ''' #initialize the total_revenu tag total_revenue = 0 if shoes_available is None: shoes_available = [] if customers is None: customers = {} for customer in customers: # Assign the customer's desired shoe size shoe_size = customer[0] # Assign the customer's sale price for said shoe. shoe_price = customer[1] if shoes_available[shoe_size] > 0: # Add the shoe price to the total revenue if said size is still available total_revenue += shoe_price # Remove one shoe from the available sizes if we sold the pair of shoes. shoes_available[shoe_size] -= 1 return total_revenue def read_info_from_STDIN(): ''' returns tuple (number_of_shoes_avalable, customers) number_of_shoes_available --> dict with key=shoe_size value=number_pairs_available customers --> list of customers desired shoe size and sale price. ''' from collections import Counter # Read in the number of shoes from STDIN and convert to integer number_of_shoes = int(input()) # Read the list of shoe sizes from STDIN and convert each size to an integer # Create a count of each size available and store it in a dictionary. shoes_available = Counter([int(i) for i in input().strip().split()]) # Read in the list of customer shoe size and price from STDIN and convert to integer. # The number of customers is given in advance so the code can grab the correct number of customers. customers = [[int(i) for i in input().split()] for _ in range(int(input()))] return shoes_available, customers if __name__ == '__main__': shoes_available, customers = read_info_from_STDIN() print(calculate_total_revenu(shoes_available, customers))
+ 0 comments from collections import Counter n_shoes = int(input()) sizeList = input().split(' ') sizeCounter = Counter(sizeList) n_customer = int(input()) sum_ = 0 for _ in range(n_customer): desire_list = input().split(' ') if desire_list[0] in sizeCounter.keys() and sizeCounter[desire_list[0]] != 0: sum_ += int(desire_list[1]) sizeCounter[desire_list[0]] -=1 print(sum_)
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