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  1. Prepare
  2. Algorithms
  3. Warmup
  4. Compare the Triplets
  5. Discussions

Compare the Triplets

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4346 Discussions

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  • lsloan
     + 0 comments

    Here's my shortest answer (so far)…

    def compareTriplets(a, b):
    return (list(map(sum, zip(*(
      (1, 0) if i > j else (0, 1)
      for i, j in zip(a, b) if i != j))))
      or [0, 0])

    Also short, but done without for loop…

    def compareTriplets(a, b):
    return list(map(sum, zip(*(map(lambda i:
        (1, 0) if i[0] > i[1] else (0, 1) if i[0] < i[1] else (0, 0),
        zip(a, b))))))

    I'm not sure whether the for in a sequence comprehension is really considered to be the same as a for-loop, but I thought I'd try to make a solution without that keyword anyway.

    Yesterday, I had submitted this longer answer because I was sleepy…

    def compareTriplets(a, b):
    at = bt = 0
    for i in range(3):
      if a[i] > b[i]:
        at += 1
      if b[i] > a[i]:
        bt += 1
    return [at, bt]

  • mohamedhari317
     + 0 comments
    def compareTriplets(a, b):
    sa=0
    sb=0
    for i in range(3):
        if a[i]<b[i]:
            sb+=1
        if a[i]>b[i]:
            sa+=1
        if a[i]==b[i]:
            sa+=0
            sb+=0
    return sa,sb

  • mahesh0072004
     + 0 comments

    def maxx(a,b): if a==b: return 2 elif a>b: return 0 else: return 1 def compareTriplets(a, b): # Write your code here score=[0]*3 for i in range(0,len(a)): winner=maxx(a[i],b[i]) score[winner]+=1 score.pop() return score

  • nixxxxx
     + 1 comment
        x = sum([10 if aa>bb else 1 if aa <bb else 0 for aa,bb in zip(a,b)])    
    return [x//10, x%10]

  • petefields06
     + 0 comments

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