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  1. Prepare
  2. Algorithms
  3. Warmup
  4. Compare the Triplets
  5. Discussions

Compare the Triplets

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4359 Discussions

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  • FeleciaWeller
     + 0 comments

    It's a concise and effective exercise for mastering comparison-based logic in programming. Ekbet86

  • Wawrzek
     + 0 comments
        compare = [a[i] - b[i] for i in range(len(a))]
    
    sumA = sum(1 for n in compare if n > 0)
    sumB = sum(1 for n in compare if n < 0)
    
    return sumA, sumB

  • leo_d_bradley
     + 0 comments

    What should I do when an input constraint is met ? For example if one of Alice's input scores is >100, should I just not give a point to either in this case ?

  • SVVBathini_w
     + 0 comments

    For Python3 Platform

    def compareTriplets(a, b):
    alice = bob = 0
    
    for i in range(3):
        if(a[i] > b[i]):
            alice += 1
        elif(a[i] < b[i]):
            bob += 1
    
    return [alice, bob]

a = list(map(int, input().split()))
b = list(map(int, input().split()))

result = compareTriplets(a, b)

print(*result)

  • this_enable
     + 0 comments

    function compareTriplets(a, b) { let [_a, _b] = [a, b]; let res = [0, 0];

    _a.map((f, i) => {
    if(f !== _b[i]) {
        const r = Math.max(f, _b[i]) === _b[i];
        res[~~r]++;
    }
});

return res;

    }