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  1. Prepare
  2. Algorithms
  3. Warmup
  4. Compare the Triplets
  5. Discussions

Compare the Triplets

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  • sagarlakhia18
     + 45 comments

    Java:

    pointsAlice = ((a0>b0)?1:0)+ ((a1>b1)?1:0)+ ((a2>b2)?1:0) ;
 pointsBob = ((a0<b0)?1:0)+ ((a1<b1)?1:0)+ ((a2<b2)?1:0) ;
 System.out.println(pointsAlice+" " +pointsBob);

  • addison_
     + 19 comments

    Here's another Python3 example. A bit lengthy, but gets the job done:

    def solve(a0, a1, a2, b0, b1, b2):
    alice = [a0, a1, a2]
    bob = [b0, b1, b2]
    score = [0, 0]
    for a, b in zip(alice, bob):
        if a > b:
            score[0]+= 1
        elif b > a:
            score[1]+=1
    return score

  • carlos_menezes
     + 9 comments

    JavaScript:

    function compareTriplets(a, b) {
    let points = [0, 0];
    for (let i = 0; i < a.length; i++) {
        if (a[i] > b[i]) {
            points[0]++;
        } else if (a[i] != b[i]) {
            points[1]++;
        }
    }
    return points;
}

  • marcell_made
     + 8 comments

    I'm using Javascript and for me it's saying my output is correct, but it's not letting me move on because of a runtime error on line 47 with result.join being undefined.

  • wiicontatos
     + 3 comments

    I think my code it's clean to read. Python 3

    def solve(a, b):
    alice = []
    bob = []
    for _ in range(len(a)):
        if(a[_] > b[_]): alice.append(1)
        elif(a[_] < b[_]): bob.append(1)
    return sum(alice), sum(bob)
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