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  1. Practice
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  4. Compare the Triplets
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Compare the Triplets

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  • sagarlakhia18 + 0 comments

    Java:

    pointsAlice = ((a0>b0)?1:0)+ ((a1>b1)?1:0)+ ((a2>b2)?1:0) ;
 pointsBob = ((a0<b0)?1:0)+ ((a1<b1)?1:0)+ ((a2<b2)?1:0) ;
 System.out.println(pointsAlice+" " +pointsBob);

  • addison_ + 0 comments

    Here's another Python3 example. A bit lengthy, but gets the job done:

    def solve(a0, a1, a2, b0, b1, b2):
    alice = [a0, a1, a2]
    bob = [b0, b1, b2]
    score = [0, 0]
    for a, b in zip(alice, bob):
        if a > b:
            score[0]+= 1
        elif b > a:
            score[1]+=1
    return score

  • carlos_menezes + 0 comments

    JavaScript:

    function compareTriplets(a, b) {
    let points = [0, 0];
    for (let i = 0; i < a.length; i++) {
        if (a[i] > b[i]) {
            points[0]++;
        } else if (a[i] != b[i]) {
            points[1]++;
        }
    }
    return points;
}

  • marcell_made + 0 comments

    I'm using Javascript and for me it's saying my output is correct, but it's not letting me move on because of a runtime error on line 47 with result.join being undefined.

  • dogejim + 0 comments
    static int[] solve(int a0, int a1, int a2, int b0, int b1, int b2){
        // Complete this function
        int[] solve = {0, 0};
        int[] a = {a0, a1, a2};
        int[] b = {b0, b1, b2};
        for (int i = 0; i < 3; i++){
            if (a[i] > b[i]) 
                solve[0] += 1;
            if (a[i] < b[i])
                solve[1] += 1;
        }
        return solve;
    }

    This code worked for me in C#... Threw the variables into new arrays, guess would be easier just to toss it arrays? then compared each in the for loop.

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