We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Python
  3. Itertools
  4. Compress the String!
  5. Discussions

Compress the String!

Sort by

recency

|

859 Discussions

|

  • dilajevolves
     + 0 comments
    from itertools import groupby
result = [f"({len(list(group))}, {char})" for char,group in groupby(input())]
print (" ".join(result))

  • vyoma_patel
     + 0 comments
    from itertools import groupby
s = input()
for char, grouped_iter in groupby(s):
    print(f"({len(list(grouped_iter))}, {char})", end = " ")

  • msh_123
     + 0 comments

    from itertools import groupby

    input_value = input()

    group_result = groupby(input_value)

    for key,value in group_result:

    value = sorted(list(value))
print(f"({int(len(value))}, {int(key)})", end=" ")

  • rohitambasta_ii1
     + 0 comments

    Core Python code (Without Built-in function)- We will appreciate itertools module some other time :

    string= input()

lst= [element for element in string]

count= 1

prev= lst[0]

for i in range(1, len(lst)):
    if lst[i] == prev:
        count = count + 1

    else:
        print(f"({count}, {prev})", end= " ")
        prev= lst[i]
        count = 1

print(f"({count}, {prev})")

  • sparksinformati1
     + 0 comments
    import itertools

print(" ".join(f"({len(list(g))}, {k})" for k, g in itertools.groupby(input())))