if(n==1) printf("one\n"); if(n==2) printf("two\n"); if(n==3) printf("three\n"); if(n==4) printf("four\n"); if(n==5) printf("five\n"); if(n==6) printf("six\n"); if(n==7) printf("seven\n"); if(n==8) printf("eight\n"); if(n>9) printf("Greater than 9\n");

include

int main() { int n; scanf("%d",&n);

switch(n)
{
    case 1:printf("one",n);
    break;
    case 2:printf("two",n);
    break;
    case 3:printf("three",n);
    break;
    case 4:printf("four",n);
    break;
    case 5:printf("five",n);
    break;
    case 6:printf("six",n);
    break;
    case 7:printf("seven",n);
    break;
    case 8:printf("eight",n);
    break;
    case 9:printf("nine",n);
    break;
    default: printf("Greater than 9");
    break;
}

}

Don't let the extra coding confuse you just simply do as they said just stay aware that you have to take the input on the pre defined variable 'n' as scanf ("%d",&n)....then you simply continue coding as your if else statements you need according to the qstn.

include

int main() { int n; printf("Enter number: "); scanf("%d",&n); if(n == 1) printf("one"); else if(n == 2) printf("two"); else if(n == 3) printf("three"); else if(n == 4) printf("four"); else if(n == 5) printf("five"); else if(n == 6) printf("six"); else if(n == 7) printf("seven"); else if(n == 8) printf("eight"); else if(n == 9) printf("nine"); else if(n > 9) printf("Greater than 9"); return 0;

}

Here are the solution of [Conditional Statements in C Hacker Rank Solution] https://www.chase2learn.com/conditional-statements-in-c-hacker-rank-solution/