Pretty annoying, not really a mathematics challenge, but rather a "know-how-to-deal-with-long-integers" challenge.

If you're failing all but 1 of the test cases, you more than likely did not implement the modulo described in the instructions. In my opinion this problem would be much better if we didn't have to handle data overflow in such a way. In any case it's only 1 extra line of code:

var routeCount=1;
for(int i=0;i<routes.Length;i++){
	routeCount*=routes[i];
	routeCount%=1234567;
}
return routeCount;

For C# LINQ

int result = arr.Aggregate(1, (a, b) => (b * a)%1234567);

Snippet.

for(int j = 0; j < towns - 1; j++) {
                routes *= scanner.nextInt();
                for(;;) {
                if (routes > 1234567) routes = routes - 1234567;
                    else break;
            	}
}

The modulo makes me laugh a bit... they have this story layer with Gandalf traveling between towns to make the question make sense. Then, with no explanation, the answer must be submitted as a modulo.

You weird, Gandalf.

easy question

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    int t;
    cin>>t;
    while(t--)
    {
        int n;
        cin>>n;
        long long sum=1;
        for(int i=0;i<n-1;i++)
        {
            
            long long x;
            cin>>x;
            sum=((sum%1234567)*(x%1234567))%1234567;
            
        }
        cout<<sum<<endl;
    }
    return 0;
}

Those were some biga$$ numbers.

while multiplying all the elements in a list and printing the output, how is

for i in list: ans *= i print (int(fmod(ans,1234567)))

and

print (functools.reduce(op.mul, s, 1) % 1234567)

different. As, in one case solution is being accepted while in another it just passes only one testcase.

This seems to be much connected with construction industry and MCIOB can give a solution for this thing.

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