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"Counter Game" can refer to a few different things: a number-based game where players reduce a number to 1, a type of game played with dice on a store counter, or a commongameplay mechanic in collectible card games. It can also refer to the popular first-person shooter game "Counter-Strike", or various other games with similar themes. The news comes via a report from PlayStation LifeStyle, which excerpts a LinkedIn post from a Jackalyptic Games employee, says that their team and Counterplay were working on a project together, but unfortunately, “CPG was disbanded”.13 Jan 2025

Not the most efficient, but is readable and works

def counterGame(n):
    powers2 = []
    x = 2
    while x<=n:
        powers2.append(x)
        x *= 2

    louise = True
    while True:
        if n == 1:
            break
        n = n / 2 if n == powers2[-1] else n - powers2[-1]
        powers2 = [x for x in powers2 if x <= n]
        louise = not louise
    return "Richard" if louise else "Louise"

In the game between Louise and Richard, the goal is to reduce a number to 1 through a series of steps, either by dividing by the largest power of 2 or subtracting it. Louise always starts, and the game continues until one of them makes the number 1. For instance, if the number is 6, Louise will subtract 4 (the largest power of 2), and Richard will divide 2 by 2 to win. This game mirrors the strategic moves often discussed in USA News, where analyzing decisions and predicting outcomes are key elements in political, economic, or social contexts.

easy recursive solution:

def is_pow2(n):
    return n > 0 and (n & (n-1)) == 0

def helper(n, state):
    nxt_state = (state + 1) % 2
    if n == 1:
        return nxt_state
    if n < 4:
        return state

    if is_pow2(n):
        nxt_n = n // 2
        return helper(nxt_n, nxt_state)
    else:
        bn = n.bit_length()
        nxt_n = n ^ (1 << (bn-1))
        return helper(nxt_n, nxt_state)
    
def counterGame(n):
    # Write your code here
    '''
    1 richard
    2 louise
    3 louise
    4 richard
    
    0-l, 1-r
    '''
    
    return 'Richard' if helper(n, 0) else 'Louise'