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  1. Prepare
  2. Algorithms
  3. Sorting
  4. The Full Counting Sort
  5. Discussions

The Full Counting Sort

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722 Discussions

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  • yashdeora98294
     + 0 comments

    Here is solution in python, java, c++, c and javascript programming - https://programmingoneonone.com/hackerrank-the-full-couting-sort-problem-solution.html

  • anarod_val25
     + 0 comments
    void countSort(vector<vector<string>> arr) {
    map<int, vector<string>> strmap;
    
    for(int i = 0; i<arr.size(); i++){
        string newc = i<arr.size()/2 ? "-" : arr[i][1];
         
        strmap[stoi(arr[i][0])].push_back(newc);
    }
    
    for(auto&[key, vector] : strmap){
        for(int k = 0; k<vector.size(); k++){
            cout<<vector[k]<<" ";
        }
    }
    
}

  • danielmesquitad1
     + 0 comments

    My java Solution

    public static void countSort(List> arr) { int n = arr.size(); int middle = n / 2; StringBuilder sb = new StringBuilder(); Entry[] entries = new Entry[n];

        for (int i = 0; i < n; i++) {
        String key = arr.get(i).get(0);
        String value = (i < middle) ? "-" : arr.get(i).get(1);
        entries[i] = new Entry(key, value);
    }

    Arrays.sort(entries, Comparator.comparing(entry -> Integer.parseInt(entry.number)));

    for (Entry e : entries) {
        sb.append(e.letters).append(" ");
    }

    System.out.print(sb.toString());

}

  • afzal_saiyed931
     + 0 comments
    def countSort(arr):
    # Write your code here
    temp_arr = [[] for i in range(100)]
    
    n = len(arr)
    for i, (num, val) in enumerate(arr):
        new_val = "-" if i < (n // 2) else val
        temp_arr[num].append(new_val)
    result = []
    for i in temp_arr:
        result.extend(i)
    print(" ".join(result))

  • phanvantienpvt01
     + 0 comments

    My python sollution

    def countSort(a):
    m_value = 0
    for i in range(len(a)):
        if i < len(a) // 2 :
            a[i][1] = '-'
        a[i][0] = int(a[i][0])
        m_value = max(m_value,a[i][0])
    sort = [[] for i in range(m_value+1)]
    for j in range(len(a)):
        sort[a[j][0]].append(a[j][1])
    result = []
    for i in sort :
        result.extend(i)
    print(' '.join(map(str,result)))