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Python 3: You can solve this problem efficiently by using a technique called "prefix sum" or "cumulative sum
def arrayManipulation(n, queries): arr = [0] * (n + 1) for query in queries: a, b, k = query arr[a - 1] += k arr[b] -= k max_value = 0 current_sum = 0 for value in arr: current_sum += value max_value = max(max_value, current_sum) return max_value
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Array Manipulation
You are viewing a single comment's thread. Return to all comments →
Python 3: You can solve this problem efficiently by using a technique called "prefix sum" or "cumulative sum