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  1. Practice
  2. Data Structures
  3. Arrays
  4. Array Manipulation
  5. Discussions

Array Manipulation

  • krishnna + 1 comment

    check it out here, you will get all your doubts solved https://www.geeksforgeeks.org/difference-array-range-update-query-o1/

    • tejaspatil + 1 comment

      Below link will also help to understand theory behind it. https://www.geeksforgeeks.org/constant-time-range-add-operation-array/

      • codam + 8 comments

        Same solution in Javascript

            var arr = [];
    var max = 0;
    // init each element of arr to 0
    for (let l = 0; l < n; l++) {
        arr[l] = 0;
    }
    // for each sum operation in queries
    for (let i = 0; i < queries.length; i++) {
       // update arr with number to add at index=queries[i][0]  and number to remove at index=queries[i][0]+1 => this will allow us to build each element of the final array by summing all elements before it. The aim of this trick is to lower time complexity
        arr[queries[i][0]-1] += queries[i][2];
        if (queries[i][1] < arr.length) {
            arr[queries[i][1]] -= queries[i][2];
        }
    }
    for (let j = 1; j < n; j++) {
        arr[j] += arr[j-1];
    }
    for (let k = 0; k < arr.length; k++) {
        max = Math.max(max, arr[k]);
    }
    //max = Math.max(...arr); // not working for big arrays
    return max;
        • kamnijais + 1 comment

          Hey, I did the code in Java8 and my code is getting failed for input type - where only single value is present in a row of array. meaning only left index value is provided and right and k value is missing from array. So can you help me how to solve this issue?

          • h1017691668 + 0 comments

            you could post your code,and we can check it out

        • mevtew + 2 comments

          simpler in es6:

          function arrayManipulation(n, queries) { let arr = new Array(2*n).fill(0); let max = 0;

          queries.forEach((item) => {
    arr[item[0]] += item[2];
    arr[item[1] + 1] -= item[2];
});

arr.reduce((prev, curr, idx) => {
    const sum = prev + curr;
    if (sum > max) {
        max = sum;
    }

    return sum;
})

return max;

          }

          • Rockyfive + 1 comment

            I did something pretty similar, just with a little bit more readable forEach:

            const arr = new Array(n).fill(0);
let result = 0;

queries.forEach(([a, b, k]) => {
    arr[a - 1] += k;
    if (b < arr.length) {
        arr[b] -= k;
    }
});

arr.reduce((a, b) => {
    const acc = a + b;
    result = Math.max(result, acc);
    return acc;
}, 0);

return result;
            • susahin80 + 1 comment

              This produces wrong answer in some of the tests.

              • Kanahaiya + 1 comment

                Hi,

                try this. Here is the video tutorial for my solution O(n+m) complexity.

                https://www.youtube.com/watch?v=hDhf04AJIRs&list=PLSIpQf0NbcCltzNFrOJkQ4J4AAjW3TSmA

                Would really appreciate your feedback like and comment etc. on my video.

                • Fuchsia + 1 comment

                  It is a good video. I understood the algorithm clearly.

                  • Kanahaiya + 1 comment

                    thanks @chandraprabha90.

                    but it would be great if you can please provide your comments, like, dislike on my video how i did it..It motivates me to create better content for my audience.

                    • Grozny + 1 comment

                      Could you add subtitles? I tried watching it but couldn't quite understand your accent through the audio

                      • Kanahaiya + 0 comments

                        Hi Grozny,

                        I appologize for my bad sound quality but i am trying to improve it. but it will be very difficult to add subtitle for this video because its around half an hour which explains all the concepts in deep.

                        Making this long video took lot of effort and time now adding a subtitle will be very tedious without any support.

                        Will suggest you to try automatic transcribe feature from youtube to translate it.

                        Anyway thanks for watching.

          • michael_yiming_1 + 0 comments
            [deleted]
        • jpeavey451 + 0 comments

          Your last for loop isn't needed. You can move Math.max to the previous for loop.

        • lyons_mr + 0 comments
          [deleted]
        • tyler_e_austin + 0 comments
          [deleted]
        • tyler_e_austin + 0 comments

          Added some ES6 syntax suger...

          const arrayManipulation2 = (n, queries) => {
  const arr = new Array(n).fill(0);
  let max = 0;
  for (let i = queries.length - 1; i >= 0; i--) {
    const [a, b, k] = queries[i];
    arr[a - 1] += k;
    if (b < arr.length) {
      arr[b] -= k;
    }
  }
  for (let j = 1; j < n; j++) {
    arr[j] += arr[j - 1];
  }
  for (let k = arr.length - 1; k >= 0; k--) {
    max = Math.max(max, arr[k]);
  }
  return max;
};
        • shubhanksrivast1 + 0 comments

          Got stuck because of this

          max = Math.max(...arr); // not working for big arrays

          Thanks man!

        • brandon53 + 0 comments

          You could simplify your code a smidge, and save a little processing power, by removing your final for loop, and putting in an if check in the second to last loop, like this:

          for (let j = 1; j < n; j++) {
	arr[j] += arr[j-1];
	
	if (arr[i] > biggest) {
		biggest = arr[i];
	}
}