We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
Loading...
  1. Practice
  2. Tutorials
  3. Cracking the Coding Interview
  4. Arrays: Left Rotation
  5. Discussions

Arrays: Left Rotation

  • pul_k3333 + 0 comments

    Well done! I did it by finding the correct number for the index, rather than the new position of a given number:

    for (int i =0; i < n; i++){
    int num = a[((n + k) % n + i) % n];
    System.out.print((num) + " ");
}