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It's not "checking" any conditions. It's doing boolean operations and mathematical comparisons which are both objectively faster than branching/conditional if statements.
Also, even it weren't, it'd still be equivalent because everything after the or is ONLY evaluated when the first operand is false, which is identical to the logic of the if statement. You can prove that this is "short-circuiting" the rest of the statement by running it on a tree and seeing that you don't get null pointer exceptions which WOULD happen if the rest of the expression was evaluated whenever node == null.
So no, it's not "checking each condition every time".
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Trees: Is This a Binary Search Tree?
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It's not "checking" any conditions. It's doing boolean operations and mathematical comparisons which are both objectively faster than branching/conditional if statements.
Also, even it weren't, it'd still be equivalent because everything after the or is ONLY evaluated when the first operand is false, which is identical to the logic of the if statement. You can prove that this is "short-circuiting" the rest of the statement by running it on a tree and seeing that you don't get null pointer exceptions which WOULD happen if the rest of the expression was evaluated whenever node == null.
So no, it's not "checking each condition every time".