# my solution uses enumerate() to create the list of indices to be printed. If a word/letter is not found in group A, minus one is printed instead.
from collections import defaultdict

d = defaultdict(list)
n, m = input().split()
for i in range(int(n)):
    d["A"].append(input())
for j in range(int(m)):
    d["B"].append(input())
    
for letter in d["B"]:
    if letter in d["A"]:
        b_list = [str(i+1) for i, x in enumerate(d["A"]) if x == letter]
        print(" ".join(b_list))
    else:
        print(-1)