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#!/bin/bash
read n;
sum=0;
for i in n ); do
read line;
sum=sum + echoi -d " " - (echo((i )) -d " ") ))
echo
i -d " "
((
i )) -d " "
done
echo $sum | sed -e 's/-//'`
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Diagonal Difference
You are viewing a single comment's thread. Return to all comments →
#!/bin/bash
read n;
sum=0;
for i in n ); do
read line;
sum=sum +
echoi -d " "- (echo((i )) -d " ") ))done
echo $sum | sed -e 's/-//'`