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Two for loops expensive..
function solve(n, arr){
var primarySum = 0;
var secondarySum = 0;
arr.forEach(function(v, row){
primarySum+=v[row];
secondarySum+=v[n-row-1];
});
Diagonal Difference
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Two for loops expensive.. function solve(n, arr){ var primarySum = 0; var secondarySum = 0; arr.forEach(function(v, row){ primarySum+=v[row]; secondarySum+=v[n-row-1]; });
return Math.abs(primarySum - secondarySum); }