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I have a question regarding this condition
If our numInputs is an odd number
if(j == k)
{
leftD += curInput;
}
at some point we will have a (j==k) in rightD as well
and at this point the code will add to the leftD and rightD as well which would make the same to give you a wrong answer. Wont It?
Please forgive me. Noob Question if i havent seen something correctly.
Because the numInputs is an odd number, the two diagonals will always cross at some point, resulting in one cell that is part of the sum of both diagonals. For a 3x3 matrix, the two diagonals are {(3,1), (2,2), (1,3)} and {(1,1), (2,2), (3,3)}; (2,2) is the center point and is part of both diagonals.
Diagonal Difference
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Hi,
I have a question regarding this condition If our numInputs is an odd number
if(j == k) { leftD += curInput; }
at some point we will have a (j==k) in rightD as well and at this point the code will add to the leftD and rightD as well which would make the same to give you a wrong answer. Wont It?
Please forgive me. Noob Question if i havent seen something correctly.
Because the numInputs is an odd number, the two diagonals will always cross at some point, resulting in one cell that is part of the sum of both diagonals. For a 3x3 matrix, the two diagonals are {(3,1), (2,2), (1,3)} and {(1,1), (2,2), (3,3)}; (2,2) is the center point and is part of both diagonals.