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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Divisible Sum Pairs
  5. Discussions

Divisible Sum Pairs

  • prabhjot8126
     + 4 comments

    you could have done like this could reduce little more

    for(int i=0;i<n;i++)
        {
        for(int j=i+1;j<n;j++)
            {
                if((a[i]+a[j])%k==0)
                    {
                    count++;
                }
        }
    }