We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Algorithms
  3. Implementation
  4. Drawing Book
  5. Discussions

Drawing Book

Sort 1433 Discussions, By:

  • lemming0061
     + 87 comments

    Extremely simple solution in Python

    #!/bin/python

import sys


n = int(raw_input().strip())
p = int(raw_input().strip())

print min(p/2,n/2-p/2)

  • Kanahaiya
     + 9 comments

    Hello friends,

    In this video tutorial, I have explained hackerrank drawing book solution algorithm. hackerrank drawing book problem can be solved by using mathematics. The complexity of drawing book hackerrank solution is O (1)

    If interested to know more about the generic algorithm in details-

    click here for the video explanation of generic algorithm with complexity analysis.

    or you can click on the image too to follow youtube tutorial.

    Here is the working solution:-

    source code :

    static int pageCount(int n, int p) {

		int totalPageTurnCountFromFront = n / 2;
		int targetPageTurnCountFromFront = p / 2;
		int targetPageTurnCountFromBack = totalPageTurnCountFromFront - targetPageTurnCountFromFront;

		return Math.min(targetPageTurnCountFromFront, targetPageTurnCountFromBack);

	}

    Would really appreciate your feedback like, dislike , comment etc. on my video.

    Do not forget to upvote, if you find it useful.

  • Aswath3167
     + 23 comments

    My solution in C...Hope it helps!!!

    #include<stdio.h>
int main()
{
int n=0,p=0,min;
scanf("%d",&n);
scanf("%d",&p);
min=(n/2)-(p/2);
if(min>p/2)
min=p/2;
printf("%d",min);
return 0;
}

  • sakai_stanley
     + 9 comments

    My JavaScript solution:

    function pageCount(n, p) {
    /*
		  n: the number of pages in the book
		  p: the page number to turn to
    */

    const pageTurns = Math.floor(p / 2);
    const totalTurns = Math.floor(n / 2);

    /* Returns the total number of page turns it takes to get
    to a page or how many it requires if starting from the back */

    return Math.min(pageTurns, totalTurns - pageTurns);
}

  • aruncveli
     + 2 comments

    Input for test case #26 has to be on two lines.

Load more conversations