I initially overcomplicated it by trying to simulate the entire book, but then I realized it's just about comparing the number of page turns from the front and back. Here's a simple Python solution: python

def pageCount(n, p): return min(p // 2, (n // 2 - p // 2))

Interestingly, this concept is also applied in healthcare systems. For instance, revenue cycle management services help streamline processes by efficiently handling tasks, much like minimizing unnecessary steps in a problem-solving approach. You can learn more about this here: https://swiftmds.com/services/healthcare-revenue-cycle-management-services/.

Hope this helps!

Isn't it should be 'back' instead of 'front' in the following sentence from the problem? "...The last page may only be printed on the front, given the length of the book."

I don't understand that sentence

public static int pageCount(int n, int p) { int totalFaces = 1 + (n-1)/2 + (n-1) % 2; // a face is the left the right page int forwardTurns = p/2; int reverseTurns = (totalFaces-1) - forwardTurns; //totalFaces-1 is the index of the last face; the first face's index is 0

    return Math.min(forwardTurns, reverseTurns);

}

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