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  1. Prepare
  2. SQL
  3. Aggregation
  4. Top Earners
  5. Discussions

Top Earners

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3479 Discussions

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  • leotrinh2810
     + 0 comments
    SELECT
CONCAT(
   MAX(salary*months)
    ,' '
    ,COUNT(name)
      )
FROM Employee
WHERE salary*months =  (SELECT MAX(salary*months) FROM Employee);

  • assault721
     + 0 comments

    SELECT MAX(salary * months), COUNT(*) FROM Employee WHERE salary * months = (SELECT MAX(salary * months) FROM Employee);

  • SVVBathini_w
     + 0 comments

    For MySQL Platform

    SELECT salary*months AS total_earnings, COUNT(*) FROM employee
GROUP BY 1
ORDER BY 1 DESC LIMIT 1;

  • samuel2ayman
     + 0 comments
    SELECT MAX(salary*months),COUNT(salary) FROM Employee
WHERE salary*months>=(SELECT MAX(salary*months) FROM Employee)

  • nerisa_jp
     + 0 comments

    For MS SQL Server:

    SELECT TOP 1 (Salary * Months) as EARNINGS, COUNT(name) FROM Employee GROUP BY Salary, Months ORDER BY EARNINGS DESC