my sql

SELECT SALARY * MONTHS AS TOTAL, count(*) FROM EMPLOYEE group by total desc limit 1

select max(salary*months), count(salary) from employee group by salary*months order by salary*months desc limit 1

SELECT MAX(months * salary) AS max_earnings, COUNT(*) FROM employee WHERE salary * months = (SELECT MAX(months * salary) FROM employee);

MS SQL Server:

with abc as (select name,(months*salary) as earnings from employee),

def as (select earnings,count(name) as names from abc group by earnings)

select top 1 * from def order by earnings desc

For MySQL

SELECT MAX(MONTHS*SALARY), COUNT(*) FROM EMPLOYEE GROUP BY(MONTHS*SALARY) ORDER BY MONTHS*SALARY DESC LIMIT 1;