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Electronics Shop

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  • patrickgao2020
     + 0 comments

    Here is my Python code! We first find all possible combinations of keyboards and drives and then find the largest sum of those. I appended -1 so if there is no combination within budget, it returns -1.

    def getMoneySpent(keyboards, drives, b):
    possible = list(itertools.product(*[keyboards, drives]))
    for a in range(len(possible)):
        possible[a] = sum(possible[a])
    inbudget = [x for x in possible if x <= b]
    inbudget.append(-1)
    return max(inbudget)

  • Rohanandmail
     + 1 comment

    What is the best time complexity that can be achieved?

  • alban_tyrex
     + 0 comments

    Here is my c++ solution, you can find the video here : https://youtu.be/yC-TXToDbD0

    int getMoneySpent(vector<int> keyboards, vector<int> drives, int b) {
    int ans = -1;
    for(int k : keyboards){
        for(int d : drives){
            if(k + d > ans && k + d <= b) ans = k + d;
        }
    }
    return ans;
}

  • rabearimananaha1
     + 0 comments

    Very simple python solution here

    def getMoneySpent(keyboards, drives, b):
    sortedKeyBoards = sorted(keyboards, reverse=True)
    drives = sorted(drives, reverse=True)
    sumMax = 0
    
    for i in range(len(sortedKeyBoards)):
        for j in range(len(drives)):
            sumTemp = sortedKeyBoards[i] + drives[j]
            if ( sumTemp >= sumMax and sumTemp <= b):
                sumMax = sumTemp
                
    return -1 if sumMax == 0 else sumMax

  • arizonacarsales1
     + 0 comments

    I run a car dealership shop in arizona that sells new and used cars. I want to apply this code on my website. I want to sue this code on my magento based website built with magento 2.1 version