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  1. Prepare
  2. Algorithms
  3. Dynamic Programming
  4. Equal
  5. Discussions

Equal

  • quincy_wofford
     + 2 comments

    Slightly more concise take on this eval approach:

    arg1 = input()
l = []
for _ in range(int(arg1)):
    s = input().split()
    if (s[0] != 'print'):
        eval("l.{}(".format(s[0])+','.join(s[1:])+")")
    else:
        print(l)

    Also worth noting that unpacking a list with *l or a dictionary with **dict could be useful in similar problems.