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Thanks. Got it.
But there is an cal error in your operations. Instead of 12 12 12 (19) 19 19, it should be 12 12 12 (17) 17 17.
Therefore, finally it would be 27 27 27 27 27 27.
logic is about making equal not zero.So in 2 5 5 5 5 5.If we reduce 3 from all 5 we left with each having 2 chocolate and that's what we want equal chocolates.
Equal
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Thanks. Got it. But there is an cal error in your operations. Instead of 12 12 12 (19) 19 19, it should be 12 12 12 (17) 17 17. Therefore, finally it would be 27 27 27 27 27 27.
Possible in 5 step.
You Miss this condition you give chocolate bars to all but chosen one. so you wont able to give chocolates to all at once.
They should really bold this in the question. I didn't realize this making the problem seem very hard for me.
In second step, U have added 3, but addition of 1, 2 and 5 is ony possible
logic is about making equal not zero.So in 2 5 5 5 5 5.If we reduce 3 from all 5 we left with each having 2 chocolate and that's what we want equal chocolates.
what's woring in it?
We need to add to all except one element. You are adding to just one element.