We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
I think we don't need to use dynamic programming here. First of all, if you give chocolate bars to all but chosen one, it is equivalent to take away the chocolate bar(s) from each chosen one until every one is equal. So the challenge becomes decrease from each individual 1, 2 or 5 until all are equal. Second to calculate the ops we need to use to decrease an integer n until it reaches 0 (call it the function f) is equivalent to convert 1, 5 (no need to use dynamic programming here). Finally, to solve this challenge, we find the min (call it m) of the given list, then for i from 0 to 4, we find min of ops[i]=sum(f(c-min+i)) where c is each individual colleague and thus no need to use dynamic programming here :)
Equal
You are viewing a single comment's thread. Return to all comments →
I think we don't need to use dynamic programming here. First of all, if you give chocolate bars to all but chosen one, it is equivalent to take away the chocolate bar(s) from each chosen one until every one is equal. So the challenge becomes decrease from each individual 1, 2 or 5 until all are equal. Second to calculate the ops we need to use to decrease an integer n until it reaches 0 (call it the function f) is equivalent to convert 1, 5 (no need to use dynamic programming here). Finally, to solve this challenge, we find the min (call it m) of the given list, then for i from 0 to 4, we find min of ops[i]=sum(f(c-min+i)) where c is each individual colleague and thus no need to use dynamic programming here :)