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  1. Practice
  2. Algorithms
  3. Implementation
  4. Extra Long Factorials
  5. Discussions

Extra Long Factorials

  • aniketnath283 + 1 comment

    Here is the solution in Java.

    static void extraLongFactorials(int n) {
        BigInteger fact=BigInteger.valueOf(1);
        for(int i=1;i<=n;i++){
            fact=fact.multiply(BigInteger.valueOf(i));
        }
        System.out.println(fact);
    }
    • mvochoa + 1 comment

      It is not necessary to declare i

      static void extraLongFactorials(int n) {
        BigInteger fact=BigInteger.valueOf(1);
        while(n > 0){
            fact=fact.multiply(BigInteger.valueOf(n));
						n--;
        }
        System.out.println(fact);
    }
      • aniketnath283 + 0 comments

        Please see the problem of hackerrank. Method signature is already defined at hackerrank