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  1. Practice
  2. Algorithms
  3. Implementation
  4. Extra Long Factorials
  5. Discussions

Extra Long Factorials

  • esrfree + 3 comments

    If you're using JavaScript, here is a straightforward solutions that works for me...

    function extraLongFactorials(n) {

    var bigInt = BigInt(n);
    var factorial = 1n;

    for (let i = 0n; i < bigInt ; i++) {
        factorial *= bigInt - i;
    }
    
    console.log(factorial.toString());
}
    • pcortezzi + 0 comments

      Quick, simple and really readable! Congrats, man!

    • joseph_hauger + 0 comments

      Ah...I was converting to BigInt at the end and I knew I needed to convert it prior and you just helped me understand that. thank you!

    • ArthurSerafim + 0 comments

      Almost same as mine.

      function extraLongFactorials(n) {

    n = BigInt(n)
    var accumulator = BigInt(1)

    for (let i = n; i > 0; i--) {
        accumulator = accumulator * i
    }

    console.log(accumulator.toString())
}