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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Extra Long Factorials
  5. Discussions

Extra Long Factorials

  • esrfree
     + 4 comments

    If you're using JavaScript, here is a straightforward solutions that works for me...

    function extraLongFactorials(n) {

    var bigInt = BigInt(n);
    var factorial = 1n;

    for (let i = 0n; i < bigInt ; i++) {
        factorial *= bigInt - i;
    }
    
    console.log(factorial.toString());
}