We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Practice
  2. Algorithms
  3. Implementation
  4. Extra Long Factorials
  5. Discussions

Extra Long Factorials

  • GabeKagan + 4 comments

    This is hilariously trivial in Ruby, which automatically creates big integers (Bignum) as needed. I should probably try it in a language that doesn't one of these days.

    • dheeraj + 0 comments

      I know. Try it in c, c++

    • roryneil + 3 comments

      Python as well. Sum = n = input. while n > 1, decrement n and sum *= n, print sum, 5 lines.

      I think you're right, this is almost cheating in these languages.

      • zastari + 1 comment

        from math import factorial

        • crypter_dine + 1 comment

          Can u please explain Hoe to do this...

          • twinkle123 + 0 comments

            import math print math.factorial(n)

      • P1zzAdr0hn3 + 1 comment
        def printfactorial(n):
    ausgabe = n
    for q in range(1, n):
        ausgabe *= (n - q)
    return print(ausgabe)
        • crypter_dine + 0 comments

          Thanks a Lot.......I got cleared.

      • dingo_custer + 0 comments
        print reduce(lambda x,y: x*y,xrange(2,long(raw_input().strip())+1))
    • Ehouarn + 0 comments

      Another reason why I love (and sometimes hate) so much Ruby =]

    • nothlione + 0 comments

      Yeah, I did that in Python first, wrote two lines of code. Felt like cheating, haha.