This code will timeout

public static string fairRations(List B) { int count=0;
bool found=false;

    do{ 

        found=false;

        if(B.Count < 2 || (B.Count == 2 && (B[0]%2 != B[1]%2)))
        {
            break;
        }

        for(int i=0; i<B.Count; i++)
        {
            if(B[i]%2 != 0)
            {
                found=true;

                B[i]+=1;

                if(i+1 < B.Count)
                {
                    B[i+1]+=1;
                }
                else if(i-1 >=0)
                {
                    B[i-1]+=1;
                }

                count+=2;

                break;
            }                
        }

    }while(found);

    return count>0?count.ToString():"NO";
}

}

include

include

include

using namespace std;

string fairRations(vector B) { int loaves = 0; int n = B.size();

for (int i = 0; i < n - 1; ++i) {
    if (B[i] % 2 != 0) {
        B[i]++;
        B[i + 1]++;
        loaves += 2;
    }
}

if (B[n - 1] % 2 != 0) {
    return "NO";
} else {
    return to_string(loaves);
}

}

int main() { ios::sync_with_stdio(false); cin.tie(NULL);

int n; cin >> n;
vector<int> B(n);
for (int i = 0; i < n; ++i) cin >> B[i];

cout << fairRations(B) << "\n";

return 0;

}

Solution in go

func fairRations(B []int32) string {
    oddIndex := -1
    totalBreads := int32(0)
    
    for i := 0; i < len(B); i++ {
        if B[i]%2 > 0 {
            if oddIndex < 0 {
                oddIndex = i
                continue
            }
            
            totalBreads += int32((i - oddIndex) * 2)
            oddIndex = -1
        }
    }
    if oddIndex >= 0 {
        return "NO"
    }
    
    return fmt.Sprintf("%d", totalBreads)
}

My Rust solution: -

fn is_odd(number: &i32) -> bool {
    number % 2 != 0
}


fn fairRations(B: &[i32]) -> String {
    let mut b_vec = B.to_vec();
    let mut counter = 0;
    for i in 0..(b_vec.len() - 1) {
        if is_odd(&b_vec[i]) {
            b_vec[i + 1] += 1;
            counter += 2;
        }
    }
    
    if b_vec.last().unwrap() % 2 == 0 && b_vec.len() > 2 {
        return counter.to_string() 
    }
    return "NO".to_string()
}

Fair Rations has always been about providing everyday essentials with care and consistency, making sure businesses feel supported in the small details that matter most. Whether it’s stocking supplies or ensuring comfort, reliability plays a huge role in keeping operations smooth. A simple service like clean linens for your business can make a noticeable difference in presentation and customer satisfaction. This kind of thoughtful approach helps maintain standards while keeping everything stress-free.