sliding through string looking using index and counting occurences + comments for debug

    a = string
    b = sub_string
    counter = 0
    slider = 0
    while slider <= len(a):
        #print(f"looking for substring {b} in string {a} starting from position {slider}")
        if a.find(b,slider) > -1:
            #print (f"found substring {b} at position {a.find(b,slider)}")
            slider = a.find(b,slider)
            counter += 1
        slider +=1
    return counter

def count_substring(string, sub_string):
count = 0 for i in range(len(string) - len(sub_string)+1):
if string[i:i + len(sub_string)] == sub_string: count += 1 return count

def count_substring(string, sub_string): bonathan = list(string) chris = len(sub_string) mr_beats = [] timmy = 0

for skrag in range(0, len(bonathan)-chris+1):
    for k in range(chris):
        mr_beats.append(bonathan[skrag+k])
    if "".join(mr_beats) == sub_string:
        timmy += 1
    mr_beats.clear()

return timmy

if name == 'main': string = input().strip() sub_string = input().strip()

count = count_substring(string, sub_string)
print(count)

hi guys this is my ans u can also use this to visualize better https://pythontutor.com/render.html#mode=display

1 string = "ABCDCDC" 2 sub_string = "CDC" 3 temp_str = "" 4 occ = 0 5 for i in range(len(string)-len(sub_string)+1): 6 temp_str = string[:len(sub_string)] 7 string = string[1:] 8 if sub_string == temp_str: 9 occ += 1 10 print(occ)