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  1. Prepare
  2. Python
  3. Strings
  4. Find a string
  5. Discussions

Find a string

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3470 Discussions

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  • zafeer_tt
     + 0 comments

    Here's a soultion using .startswith() method

    • def count_substring(string, sub_string):
    • if len(string) in range(1, 201):
    • counter = sum(1 for i in range(len(string)) if string.startswith(sub_string, i))
    • return counter

  • chaninchu329
     + 0 comments

    made it a recursion for giggles

    def count_substring(string, sub_string): index = string.find(sub_string if index == -1: return 0 else: return 1 + count_substring(string[index+1:], sub_string)

  • phamducctrung
     + 0 comments

    Python 3 solution

    def count_substring(string, sub_string):
    count_sub_string = len(sub_string)
    count = 0
    for s in range(len(string)):
        x = string[s: s + count_sub_string]
        if (x == sub_string):
            count = count + 1
    return count

  • estrelst
     + 1 comment

    Likely not how the problem was meant to be solved, but you can also use regex lookarounds:

    import re

def count_substring(string, sub_string):
    pattern = fr"(?={re.escape(sub_string)})"
    return len(re.findall(pattern, string))``

  • charanpn340
     + 0 comments
    def count_substring(string, sub_string):
    count = 0
    for i in range(len(string)):
        if string[i:i + len(sub_string)] == sub_string:
            count += 1
    return count