We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Python
  3. Strings
  4. Find a string
  5. Discussions

Find a string

Sort by

recency

|

3441 Discussions

|

  • aadeshbendre
     + 0 comments
    def count_substring(string, sub_string):
    count = 0
    for i in range (len(string)):
         if string[i:].startswith(sub_string):
            count+=1
        
    return count

  • atakan_tatar1905
     + 0 comments
    def count_substring(string, sub_string):
    n=0``
    for i in range(len(string)):
        if string[0:len(sub_string)]== sub_string:
            n+=1
        string = string[1:]       
    return n

  • gbytggt
     + 0 comments
    import re 
def count_substring(string, sub_string):
    sub_string = f'(?=({sub_string}))'
    a = re.findall(sub_string,string)
    return len(a)

if __name__ == '__main__':
    string = input().strip()
    sub_string = input().strip()
    
    count = count_substring(string, sub_string)
    print(count)

  • MamieMashin
     + 0 comments

    It really tests your understanding of slicing and string traversal. If you're practicing for interviews or just want to strengthen your Python basics, Gurubhai247

  • itsmefakeidmail1
     + 1 comment

    string.count(sub_string) why this logic gives only 1