i solved this probelm by using findall and regular expression..

reg = r(?<=[\W]) + searching_word + (?=[\W])
:: \W represents non unicode characters... in this problem, playing a role of wrapper...

for ignoring '_'(underscore) and taking first and last word into consideration more conveniently, i made some tricks..

pre-processing::

1) deleting all the '_'s..
:: foo_bar --> foobar

2) putting '*' in first and last position..
:: foo foo foo -> *foo foo foo*

code ::

import re

n = int(input())
st = '\n'.join(['*'+input().strip().replace('_','')+'*' for _ in range(n)])
for _ in range(int(input())):
    wd = input().strip()
    reg = r'(?<=[\W])'+ wd +'(?=[\W])'
    m = re.findall(reg,st)
    print(len(m))