AB = int(input())
    BC = int(input())
    angle = math.degrees(math.atan2(AB,BC))
    degree = int(round(angle))
    print(str(degree)+ '\u00B0')

This code works but can anyone explain what atan2 is??

import math

AB = int(input().strip())
BC = int(input().strip())

angle_rad = math.atan2(AB, BC)
angle_deg = math.degrees(angle_rad)
result = round(angle_deg)

print(f"{result}{chr(176)}")

Place coordinates:

𝐵 ( 0 , 0 ) , 𝐴 ( 𝑎 , 0 ) , 𝐶 ( 0 , 𝑏 ) B(0,0),A(a,0),C(0,b).

Midpoint

𝑀

( 𝑎 / 2 ,    𝑏 / 2 ) M=(a/2,b/2).

Form vectors:

𝐵 𝑀

⃗

( 𝑎 / 2 ,    𝑏 / 2 ) BM =(a/2,b/2)

𝐵 𝐶

⃗

( 0 ,    𝑏 ) BC =(0,b)

Dot product formula:

cos ⁡

𝜃

𝐵 𝑀 ⃗ ⋅ 𝐵 𝐶 ⃗ ∣ 𝐵 𝑀 ⃗ ∣ ∣ 𝐵 𝐶 ⃗ ∣ cosθ= ∣ BM ∣∣ BC ∣ BM ⋅ BC ​

Simplify:

cos ⁡

𝜃

𝑏 𝑎 2 + 𝑏 2 cosθ= a 2 +b 2 ​

b ​

Find angle:

𝜃

cos ⁡ − 1  ⁣ ( 𝐵 𝐶 𝐴 𝐵 2 + 𝐵 𝐶 2 ) θ=cos −1 ( AB 2 +BC 2 ​

BC ​

)

Round to nearest integer if needed.

A different solution without tangent.

import math

def main():
    # a = AB and b = BC
    a, b = int(input()), int(input())
    # c = AC (hypotenuse)
    c = math.hypot(a, b)

    # Calculate angle A (opposite side a)
    # using the law of cosines
    cos_A = (b**2 + c**2 - a**2) / (2 * b * c)
    angle_A_rad = math.acos(cos_A)
    angle_A_deg = math.degrees(angle_A_rad)
    print(f"{round(angle_A_deg)}\u00B0")

if __name__ == "__main__":
    main()

This is how you find angle MBC with degree sign: Syntax:

import math ab=int(input()) bc=int(input()) print(f"{str(round(math.degrees(math.atan2(ab,bc))))}\u00B0")