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  1. Prepare
  2. Python
  3. Math
  4. Find Angle MBC
  5. Discussions

Find Angle MBC

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870 Discussions

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  • greivin_lopez
     + 0 comments

    A different solution without tangent.

    import math

def main():
    # a = AB and b = BC
    a, b = int(input()), int(input())
    # c = AC (hypotenuse)
    c = math.hypot(a, b)

    # Calculate angle A (opposite side a)
    # using the law of cosines
    cos_A = (b**2 + c**2 - a**2) / (2 * b * c)
    angle_A_rad = math.acos(cos_A)
    angle_A_deg = math.degrees(angle_A_rad)
    print(f"{round(angle_A_deg)}\u00B0")

if __name__ == "__main__":
    main()

  • 22me10sh7
     + 0 comments

    This is how you find angle MBC with degree sign: Syntax:

    import math ab=int(input()) bc=int(input()) print(f"{str(round(math.degrees(math.atan2(ab,bc))))}\u00B0")

  • vgvinaytej
     + 0 comments

    import math

    a,b= int(input()), int(input())

    print(str(round(math.degrees(math.atan2(a,b))))+chr(176))

  • sharmaj1
     + 0 comments

    Being well versed in the math class helps the most:

    # Enter your code here. Read input from STDIN. Print output to STDOUT
import math

AB = int(input())
BC = int(input())



AC = math.sqrt((AB ** 2) + (BC ** 2))
print(f"{round(math.degrees(math.acos(BC/AC)))}\N{DEGREE SIGN}")

  • hadimalik001
     + 1 comment

    import math

    ab = int(input()) bc = int(input())

    angle_rad = math.atan2(ab, bc) angle_deg = math.degrees(angle_rad)

    print(round(angle_deg)) out is 45 just number but need 45° how