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  4. Find Angle MBC
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Find Angle MBC

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829 Discussions

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  • air_mvp_jordan
     + 0 comments
    import math

ab= int(input())
bc = int(input())

hypo = math.atan(ab/bc)
angle = math.degrees(hypo)

print(f"{angle:.0f}\u00b0")

  • rafa16mj
     + 0 comments

    The math in this problem is incorrect. In order to calculate the angle MBC, we have to make the following considerations:

    *Triangle MBC as all triangles has an inner sum of angles of 180°. *The line BM is perpendicular to AC, therefore angle CMB is 90°.

    From those considerations we can state that the sum of the inner angles of triangle MBC is: theta+90°+alpha(angle BCM) = 180° To calculate alpha we use the tangent function which is Tan(alpha)= Opposite side (AB)/Adjacent side (BC), which in python would be math.degrees(math.atan(int(AB)/int(BC)))

    Then we just have to substitute alpha in our formula for the inner angles and solve for theta: Theta = 180°-90°-alpha

    The problem with the “correct solution” that the site accepts is that when calculating alpha instead of using Tan(alpha)= AB/BC, it uses Tan(alpha)= BC/AB, so we end up calculating angle CAB. By calculating this angle, we are using the upper triangle (ABM), and our final answer is angle ABM, not MBC as the problem indicates.

  • filbemolle
     + 0 comments

    funny two-liner 

    from math import atan, degrees
print(str(round(90-degrees(atan(1/(int(input())/int(input())))))) + '\u00b0')

  • benguechir_jihe1
     + 0 comments
    • If a triangle is right-angled then the center of its circumscribed circle is the midpoint of its hypotenuse and the median relative to the hypotenuse is half that of the hypotenuse.
    • ///
    • import math
    • AB= int(input())
    • BC = int(input())
    • AC = math.hypot(AB,BC)
    • BM = AC / 2
    • /////////////
    • so we consider that M is the center of the circle arround the triangle
    • and the diametre of the cecle is AC
    • the triangle MBC is isosceles in M (MC = MB = MA )
    • then we need just to calculate the angle ACB to just know the Angel MBC
    • we will use the Big traingle ABC
    • ////////////////
    • ACB = math.atan2(AB,BC)
    • print(str(round(math.degrees(ACB)))+ chr(176))

  • harenlouis27
     + 0 comments
    import math
opp= int(input())
adj = int(input())
hypo = math.atan(opp/adj)
r= math.degrees(hypo)
print(f"{r:.0f}\u00b0")