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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Find Digits
  5. Discussions

Find Digits

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1678 Discussions

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  • awadallayossef
     + 0 comments

    Easy Solution

    def findDigits(Num:int):
    numbers = list(str(Num))
    count = 0
    
    for num in numbers:
        num = int(num)
        if num == 0:
            continue
        elif Num % num == 0:
            count += 1
    return count

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     + 0 comments

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  • giriprasath_0508
     + 2 comments
    def findDigits(n):
    # Write your code here
    s =str(n)
    l=[]
    count=0
    for i in s:
        if int(i)!=0:
            l.append(int(i))
    
    for j in l:
        if  n%j==0:
            count+=1
    return count

  • raveen_re
     + 0 comments

    Solution in TS

    function findDigits(n: number): number {
    let stringNumber = n.toString();
    let count = 0;
    
    for(let i = 0; i < stringNumber.length; i++){
        let tempNumber = parseInt(stringNumber.charAt(i));
        
        if(tempNumber != 0 && (n % tempNumber === 0)){
            count++;
        }
    }
    
    return count;
}

  • dvkstalin
     + 0 comments

    Kotlin:

    fun findDigits(n: Int): Int {
    val strN=n.toString()
    var numbers=0
    strN.forEach { 
        if(it!='0'){
            val d=n%(it.digitToInt())
            if(d==0) numbers++ 
        }
     }
    return numbers
}