//JAVA15 import java.io.; import java.util.; import java.util.stream.*;

class Result {

/*
 * Complete the 'findDigits' function below.
 *
 * The function is expected to return an INTEGER.
 * The function accepts INTEGER n as parameter.
 */

public static int findDigits(int n) {
    int count = 0;
    int original = n;

    while (n > 0) {
        int digit = n % 10;
        if (digit != 0 && original % digit == 0) {
            count++;
        }
        n /= 10;
    }

    return count;
}

}

public class Solution { public static void main(String[] args) throws IOException { BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in)); BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

    int t = Integer.parseInt(bufferedReader.readLine().trim());

    IntStream.range(0, t).forEach(tItr -> {
        try {
            int n = Integer.parseInt(bufferedReader.readLine().trim());
            int result = Result.findDigits(n);
            bufferedWriter.write(String.valueOf(result));
            bufferedWriter.newLine();
        } catch (IOException ex) {
            throw new RuntimeException(ex);
        }
    });

    bufferedReader.close();
    bufferedWriter.close();
}

}

optimal approach but first requesting other learner to understand the code first

function findDigits(n) {
    // Write your code here
    let num = n
    let cnt = 0
    
    while(num > 0){
        const lastDigi = num % 10
        if(lastDigi !== 0 && (n % lastDigi === 0)){
            cnt++
        }
        num = Math.floor(num/10)
    }
    return cnt
}

Easy Solution

def findDigits(Num:int):
    numbers = list(str(Num))
    count = 0
    
    for num in numbers:
        num = int(num)
        if num == 0:
            continue
        elif Num % num == 0:
            count += 1
    return count

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