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FizzBuzz

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  • oramusa
    5 months ago+ 0 comments
    • for(int i=1; i<=100; i++) { if(i%3==0 && i%5==0) { System.out.println("FizzBuzz"); } else if(i%3==0) { System.out.println("Fizz"); } else if(i%5==0){ System.out.println("Buzz"); } else { System.out.println(i); } }
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  • gangulaniharika1
    11 months ago+ 0 comments

    include

    -3|
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  • ebs_cbn
    11 months ago+ 1 comment

    solution to the problem:

    https://www.youtube.com/watch?v=vOWJxCkvrzc

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  • MohitSethi
    1 year ago+ 0 comments

    This code will pass all the test cases.

    (let i=1; i<=n; i++) { if((i%3) == 0 && (i%5) == 0){ console.log("FizzBuzz") } else if((i%3) == 0 && (i%5) != 0){ console.log("Fizz") } else if((i%5) == 0 && (i%3) != 0){ console.log("Buzz") } else { console.log(i) } }

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  • karamit819
    1 year ago+ 0 comments

    include

    using namespace std; int main(){ for(int i=1 ; i<=100 ; i++){ if(i%3==0 && i%5==0){ cout<<"FizzBuzz"<

     else if(i%3==0){
         cout<<"Fizz"<<endl;
      }
      else{cout<<i<<endl;}
    

    } return 0; }

    -2|
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