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FizzBuzz
FizzBuzz
+ 0 comments - for(int i=1; i<=100; i++) { if(i%3==0 && i%5==0) { System.out.println("FizzBuzz"); } else if(i%3==0) { System.out.println("Fizz"); } else if(i%5==0){ System.out.println("Buzz"); } else { System.out.println(i); } }
+ 0 comments include
+ 1 comment solution to the problem:
+ 0 comments This code will pass all the test cases.
(let i=1; i<=n; i++) { if((i%3) == 0 && (i%5) == 0){ console.log("FizzBuzz") } else if((i%3) == 0 && (i%5) != 0){ console.log("Fizz") } else if((i%5) == 0 && (i%3) != 0){ console.log("Buzz") } else { console.log(i) } }
+ 0 comments include
using namespace std; int main(){ for(int i=1 ; i<=100 ; i++){ if(i%3==0 && i%5==0){ cout<<"FizzBuzz"<
else if(i%3==0){ cout<<"Fizz"<<endl; } else{cout<<i<<endl;}
} return 0; }
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