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  1. Prepare
  2. C
  3. Conditionals and Loops
  4. For Loop in C
  5. Discussions

For Loop in C

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  • anthonyoriebir
     + 0 comments
    #include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>



int main() 
{
    int a, b, i; 
    char* words[9] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    
    
    scanf("%d\n%d", &a, &b);
         for(i = a; i <= b; i++)
            if (i <=9 ){
            printf("%s\n", words[i-1]);
            }else{   
                switch (i % 2) {
                    case 0:
                        printf("even\n");
                        break;
                    default:
                        printf("odd\n");
                        break;
                    }
                }
    
   
    return 0;
}

  • vkp035127
     + 0 comments

    include

    int main() { int a,b; scanf("%d",&a); // printf("\n"); scanf("%d",&b); int i; for(i=a;i<=b && i>=a;i++) { if(i>=1 && i<=9) { if(i==1) printf("one\n"); if(i==2) printf("two\n"); if(i==3) printf("three\n"); if(i==4) printf("four\n"); if(i==5) printf("five\n"); if(i==6) printf("six\n"); if(i==7) printf("seven\n"); if(i==8) printf("eight\n"); if(i==9) printf("nine\n");

        }
    if(i>9 && i%2==0)
    printf("even\n");
    if(i>9 && i%2!=0)
    printf("odd\n");
}
return 0;

    }

  • yssnabbou2002
     + 0 comments

    include

    include

    int main() { int a,b,i; char tab[][9]={"one","two","three","four","five","six","seven","eight","nine"}; do{ printf("Enter an integer a :"); scanf("%d",&a); printf("Enter an integer b :"); scanf("%d",&b); }while(a>b);

    for(i=a;i<=b;i++)
{
    if(i>=1 && i<=9)
    {
       printf("%s\n",tab[i-1]);
    }
    else if(i%2==0)
        printf("even\n");
    else if(i%2!=0)
        printf("odd\n");
}


return 0;

    }

  • ptmkhanh29
     + 0 comments

    C

    int main() 
{
    int a, b;
    char *words[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    //printf("Please input interval [a,b]:\n");
    scanf("%d\n%d", &a, &b);
  	// Complete the code.
    //printf("Please input integer N: \n");
    //scanf("%d", &n);
    for(int i = a; i <= b; i++){
        if(i > 9){
            if(i%2 == 0) printf("even\n");
            else printf("odd\n");
        }
        else if(i >= 1 && i < 9){
            int mod = i%9;
            printf("%s\n", words[mod-1]);
        }
        else printf("nine\n");
    }
    return 0;
}

  • mohmkad200
     + 1 comment

    I wanted to print it out like this printf("%s",a<=9?num[a-1]: a%2==0?"even\n":"odd\n" but it does not work, do you know why?

    #include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>



int main() 
{
    int a, b;
    scanf("%d\n%d", &a, &b);
  	// Complete the code.
      char *num[]={"one","two","three","four","five","six","seven","eight","nine"};
    for(a;a<=b;a++)
    {
        if(a<=9)
            printf("%s\n", num[a-1]);
        else{
            if(a>9)
                if(a%2==0)
                    printf("even\n");
                else
                    printf("odd\n");
        }    
    }

    return 0;
}
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