include

int main() { int a, b; scanf("%d\n%d", &a, &b); for (int i=0; i

    if(a%2==0){
        printf("even\n"); break;
    } else {
        printf("odd\n"); break;
    }

  }
  for(int l=0;l<b+1;l++){
       if(b%2==0){
        printf("even\n"); break;
    } else {
        printf("odd\n"); break;
    }
  }

return 0;

}

5 days ago+ 0 comments

I have used this script in many sites but recently I tried to use it in best basketball for outdoor where some errors are very difficult to fix so I need some guide.

1 week ago+ 0 comments

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>



int main() 
{
    char *words[] = {"one","two","three", "four", "five", "six", "seven","eight", "nine"};

    int a, b;
    
    scanf("%d\n%d", &a, &b);
    
  	
    for(int i=a; i<=b; i++){
        (i<=9)?printf("%s\n", words[i-1]):((i%2==0)?printf("even\n"):printf("odd\n"));
    }
    return 0;
}

1 week ago+ 0 comments

You can find the solution of For Loop in C Hacker Rank Solution https://www.brokenprogrammers.com/for-loop-in-c-hackerrank-solution/

2 weeks ago+ 0 comments

this answer is right according to editorial output but getting test fai

include

int main() { int a, b, i; scanf ("%d %d", &a, &b); for (i = a; i <= b; i++) { if (i==8) { printf("eight \n"); } if(i==9) { printf("nine \n"); } if (i==10) { printf("ten \n"); } if (i==11) { printf("eleven \n"); } } for (i = a; i <= b; i++) { if (i%2==0) { printf("even \n"); } else { printf("odd \n"); } } return 0; }

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