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  1. Prepare
  2. C
  3. Conditionals and Loops
  4. For Loop in C
  5. Discussions

For Loop in C

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  • yashdeora98294
     + 0 comments

    Here is for loop in c solution - https://programmingoneonone.com/hackerrank-for-loop-in-c-solution.html

  • ginwan697
     + 0 comments
    #include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main()
{
    char *arr[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    int a, b;
    scanf("%d\n%d", &a, &b);
    // Complete the code.
    for (int n = a; n <= b; n++)
    {
        if (n >= 1 && n <= 9)
        {
            printf("%s\n", arr[n - 1]);
        }
        else
        {
            if (n % 2 == 0)
            {
                printf("even\n");
            }
            else
            {
                printf("odd\n");
            }
        }
    }

    return 0;
}

  • SVVBathini
     + 0 comments
    #include<stdio.h>

int main()
{
    int a, b;
    char word[10][10] = {"zero","one","two","three","four","five","six","seven","eight","nine"};
    
    scanf("%d", &a);
    scanf("%d", &b);
    
    for(int n=a;n<=b;n++)
    {
        if(n>=0 && n<=9)
            printf("%s\n",word[n]);
        else if(n % 2 == 0)
            printf("even\n");
        else
            printf("odd\n");
    }
    
    return 0;
}

  • kir_arut
     + 0 comments
    #include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>



int main() 
{
    int a, b;
    scanf("%d\n%d", &a, &b);
  	// Complete the code.
    char *number[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    char *evenness[] = {"even", "odd"};
    
    for(int i = a; i < b+1; i++) printf("%s\n", (i < 10) ? number[i-1] : evenness[i % 2]);

    return 0;
}

  • galant4456
     + 0 comments
    int main() 
{
    int a, b;
    scanf("%d\n%d", &a, &b);
  	// Complete the code.
    char *arr[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    
    for (int i = a; i <= b; i++) {
        if (i <= 9)
            printf("%s\n", arr[i - 1]); 
        else {
            if (i % 2 == 0)
                printf("even\n"); 
            else
                printf("odd\n");  
        }
    }
    return 0;
}