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For Loop in C
For Loop in C
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include
include
include
include
int main() { int a, b,i; scanf("%d\n%d", &a, &b); char* number[]={"one","two","three","four","five","six","seven","eight","nine","even","odd"}; for(i=a;i<=b;i++) { if(a<=9 || b<=9) { printf("%s \n",number[i-1]); } else if (a>9 || b>9) { if (a%2==0 || b%2==0) { printf("%s",number[-2]); } else { printf("%s",number[-1]); }
}
I don't think im soo good at coding but here one solution i made up by own, i want to know is that correct logic...!!!
include
include
include
include
int main() { int a, b; scanf("%d\n%d", &a, &b); for(a;a<=b;a++) { switch (a) { case 1: printf("one\n"); break; case 2: printf("two\n");break; case 3: printf("three\n");break; case 4: printf("four\n");break; case 5: printf("five\n");break; case 6: printf("six\n");break; case 7: printf("seven\n");break; case 8: printf("eight\n");break; case 9: printf("nine\n");break; } if (a>9&&a%2==0) { printf("even\n"); } else if (a>9&&a%2!=0){ printf("odd\n"); } } return 0; }
if we enter 8 and 11 then eight nine how it that possible
include
include
include
include
int main() { int a,b,x; scanf("%d\n%d", &a, &b); for(a;a<=b;a++) { if(a==1){printf("one\n");} else if(a==2){printf("two\n");} else if(a==3){printf("three\n");} else if(a==4){printf("four\n");} else if(a==5){printf("five\n");} else if(a==6){printf("six\n");} else if(a==7){printf("seven\n");} else if(a==8){printf("eight\n");} else if(a==9){printf("nine\n");} else if(a%2==0){printf("even\n");} else{printf("odd\n");}
}