This is a great problem for practicing string manipulation and frequency counting in programming! cricketbuzz.com login mahadev

total beginner here, dont judge but this the code that i wrote, ik it is super long but its the only one i could think of, i tried running it on vs code and it did give the required output but it didnt pass in hackerrank, can someone tell why

include

include

include

include

int main() { char ch[30]; int count = 0; int c;

fgets(ch, 30, stdin); // Read input

// Count '0'
count = 0;
c = '0';
for (int i = 0; i < strlen(ch); i++) {
    if (ch[i] == c) {
        count++;
    }
}
printf("%d ", count);

// Count '1'
count = 0;
c = '1';
for (int i = 0; i < strlen(ch); i++) {
    if (ch[i] == c) {
        count++;
    }
}
printf("%d ", count);

// Count '2'
count = 0;
c = '2';
for (int i = 0; i < strlen(ch); i++) {
    if (ch[i] == c) {
        count++;
    }
}
printf("%d ", count);

// Count '3'
count = 0;
c = '3';
for (int i = 0; i < strlen(ch); i++) {
    if (ch[i] == c) {
        count++;
    }
}
printf("%d ", count);

// Count '4'
count = 0;
c = '4';
for (int i = 0; i < strlen(ch); i++) {
    if (ch[i] == c) {
        count++;
    }
}
printf("%d ", count);

// Count '5'
count = 0;
c = '5';
for (int i = 0; i < strlen(ch); i++) {
    if (ch[i] == c) {
        count++;
    }
}
printf("%d ", count);

// Count '6'
count = 0;
c = '6';
for (int i = 0; i < strlen(ch); i++) {
    if (ch[i] == c) {
        count++;
    }
}
printf("%d ", count);

// Count '7'
count = 0;
c = '7';
for (int i = 0; i < strlen(ch); i++) {
    if (ch[i] == c) {
        count++;
    }
}
printf("%d ", count);

// Count '8'
count = 0;
c = '8';
for (int i = 0; i < strlen(ch); i++) {
    if (ch[i] == c) {
        count++;
    }
}
printf("%d ", count);

// Count '9'
count = 0;
c = '9';
for (int i = 0; i < strlen(ch); i++) {
    if (ch[i] == c) {
        count++;
    }
}
printf("%d ", count);

return 0;

}

include

include

include

include

int main() {

char s[100];
int freq[10] = {0};
scanf("%s",s);
for(int i = 0; s[i] != '\0'; i++){
    if(s[i] >= '0' && s[i] <= '9'){
        freq[s[i]-'0']++;
    }
}
for(int i = 0; i<10; i++){
    printf("%d",freq[i]);
}
return 0;

}

Here is Digit Frequency Solution in c - https://programmingoneonone.com/hackerrank-digit-frequency-solution-in-c.html

include

include

include

include

int main() {

/* Enter your code here. Read input from STDIN. Print output to STDOUT */  
char s[1000];
int freq[10] = {0}; 

scanf("%[^\n]", s); 
for (int i = 0; i < strlen(s); i++) {
    if (s[i] >= '0' && s[i] <= '9') {
        freq[s[i] - '0']++;
    }
}

for (int i = 0; i < 10; i++) {
    printf("%d ", freq[i]);
}  
return 0;

}