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  1. Prepare
  2. C
  3. Arrays and Strings
  4. Digit Frequency
  5. Discussions

Digit Frequency

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1188 Discussions

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  • salauddinsalaud1
     + 0 comments

    int main() {

    /* Enter your code here. Read input from STDIN. Print output to STDOUT */ 
char str[1000];
int count[10] = {0};

fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] ='\0';

for(int i=0; i<strlen(str); i++){
    if(str[i] >= '0' && str[i]<= '9'){
        int digit = str[i] - '0';
        count[digit]++;
    }  
}
for (int k=0; k<10; k++){
    printf("%d ", count[k]);
}
return 0;

    }

  • gagandeep982006
     + 0 comments
    using the ASCII value concept

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main() {

    char* arr;
    arr = (char*)malloc(sizeof(char)*1001);
    int total = 0;
    scanf("%s",arr);
    arr = (char*)realloc(arr,sizeof(char)*(strlen(arr)+1));
    int* countno;
    countno = (int*)calloc(sizeof(int),10);
    for(int i = 0;i < strlen(arr);i++){
        ((int)arr[i] >47 && (int)arr[i] <58)?countno[(int)arr[i] - 48] += 1 :(countno[0] = countno[0]); 
    }   
    free(arr);
    arr = NULL;
    
    for(int i =0; i<10;i++){
        printf("%d ",countno[i]);
    }
    
    free(countno);
    countno = NULL;
    
    return 0;
}

  • akulbachandra67
     + 0 comments

    **Mine Solution **

    #include<ctype.h>


char S[1000];
int a[] = {0,0,0,0,0,0,0,0,0,0};
scanf("%s",&S);
for(int i=0; i<strlen(S); i++){ if(isdigit(S[i])){ a[S[i]-'0'] += 1; } }
for(int i=0; i<10; i++){ printf("%d ",a[i]); }

  • KathleenOliver34
     + 0 comments

    This is a great beginner-friendly string manipulation and counting problem! Cricketbuzz com ID

  • poyif11865
     + 0 comments

    This is a great problem for practicing string manipulation and frequency counting in programming! cricketbuzz.com login mahadev