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  1. Frequency Queries
  2. Discussions

Frequency Queries

  • maxxi9 + 3 comments

    vector freqQuery(vector> queries) {

    vector v;

    map m;

    map m1;

    for (int i = 0; i 

    if (queries[i][0] == 1) {

  if (m[queries[i][1]] > 0) {

    m1[m[queries[i][1]]]--;

  }      

  m[queries[i][1]]++;

  m1[m[queries[i][1]]]++;

}

else if (queries[i][0] == 2) {

  if (m[queries[i][1]] > 0) {

    m1[m[queries[i][1]]]--;

    m[queries[i][1]]--;

    m1[m[queries[i][1]]]++;

  };

}

else {

  if (m1[queries[i][1]]>0)

    v.push_back(1);

  else 

    v.push_back(0);

}

    } return v; }

    • bhaskarshaw100 + 1 comment

      Test case 10 got terminated due to timeout......

      • matheus_is + 0 comments

        If you're getting a time out that means your algorithm can be improved. Try to come up with a solution that doesn't use loops at

    • anishukla666 + 0 comments

      Nice solution. All test cases passed.

    • siddharthasb121 + 0 comments

      very good solution,easy to understand