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  1. Frequency Queries
  2. Discussions

Frequency Queries

  • lxl6996 + 0 comments

    My solution is slightly more verbose but does more or less the same thing but also doesn't pass 7 - 13.

    // Complete the freqQuery function below.
function freqQuery(queries) {
    let hashMap = {};
    let freqMap = [];
    let results = [];

    for(let q in queries) {
        let action = queries[q][0];
        let actionValue = queries[q][1];
        let oldValue = hashMap[actionValue] || 0

        if(action === 1) {
            hashMap[actionValue] = oldValue + 1;
            setFreqMapValue(oldValue, hashMap[actionValue], freqMap);
        } else if(action === 2) {
            hashMap[actionValue] = oldValue - 1
            setFreqMapValue(oldValue, hashMap[actionValue], freqMap);
        } else if (action === 3) {
            results.push(freqMap[actionValue] > 0 ? 1 : 0);
        }
    }

    return results;

}

function setFreqMapValue(oldValue, newValue, freqMap) {
    let oldFreq = freqMap[oldValue] || 0;
    let newFreq = freqMap[newValue] || 0;
    if(oldFreq > 0) {
        freqMap[oldValue] -= 1;
    }
    freqMap[newValue] = newFreq +1;
}