SELECT id,name  FROM(
SELECT hid.hacker_id as id,
    hid.name as name,
    Count(hacker_id) as cnt
FROM Hackers hid
JOIN Submissions s ON hid.hacker_id = s.hacker_id
JOIN Challenges c ON s.challenge_id = c.challenge_id
JOIN Difficulty d ON c.difficulty_level = d.difficulty_level
WHERE d.score = s.score
GROUP BY hid.hacker_id , hid.name
ORDER BY Count(hacker_id) DESC, hid.hacker_id)
WHERE cnt > 1 ;