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SELECT h.hacker_id, h.name
FROM Hackers h
JOIN Submissions s ON h.hacker_id = s.hacker_id
JOIN Challenges c ON s.challenge_id = c.challenge_id
JOIN Difficulty d ON c.difficulty_level = d.difficulty_level AND s.score = d.score
GROUP BY h.hacker_id, h.name
HAVING COUNT(DISTINCT c.challenge_id) > 1
ORDER BY COUNT(DISTINCT c.challenge_id) DESC, h.hacker_id;
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SELECT h.hacker_id, h.name FROM Hackers h JOIN Submissions s ON h.hacker_id = s.hacker_id JOIN Challenges c ON s.challenge_id = c.challenge_id JOIN Difficulty d ON c.difficulty_level = d.difficulty_level AND s.score = d.score GROUP BY h.hacker_id, h.name HAVING COUNT(DISTINCT c.challenge_id) > 1 ORDER BY COUNT(DISTINCT c.challenge_id) DESC, h.hacker_id;