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select a.hacker_id, b.name from submissions as a inner join hackers as b on a.hacker_id=b.hacker_id
inner join challenges as c on a.challenge_id=c.challenge_id inner join difficulty as d on c.difficulty_level =d.difficulty_level where
a.score=d.score group by a.hacker_id, b.name having count()>1 order by count() desc, a.hacker_id;
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select a.hacker_id, b.name from submissions as a inner join hackers as b on a.hacker_id=b.hacker_id inner join challenges as c on a.challenge_id=c.challenge_id inner join difficulty as d on c.difficulty_level =d.difficulty_level where a.score=d.score group by a.hacker_id, b.name having count()>1 order by count() desc, a.hacker_id;