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    select s.hacker_id,--d.score, c.difficulty_level, h.name from Submissions s inner join Challenges c on s.challenge_id = c.challenge_id inner join difficulty d on d.difficulty_level = c.difficulty_level inner join hackers h on h.hacker_id = s.hacker_id where d.score = s.score --and s.hacker_id = 10857 group by s.hacker_id, h.name having count()>1 order by count() desc, s.hacker_id asc;