Top Competitors

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    SELECT h.hacker_id, h.name FROM hackers AS h JOIN submissions AS s ON h.hacker_id = s.hacker_id JOIN challenges AS c ON c.challenge_id = s.challenge_id JOIN difficulty AS d ON d.difficulty_level = c.difficulty_level WHERE d.score = s.score GROUP BY h.hacker_id, h.name HAVING COUNT(DISTINCT s.challenge_id) > 1 ORDER BY COUNT(DISTINCT s.challenge_id) DESC, h.hacker_id ASC